There are 2, the 2s and 2p subshells.
The s subshell contains just one orbital and can hold only two electrons (of opposite spin)
The p subshell contains 3 orbitals each of which can hold just 2 electrons (of opposite spin) making 6 electrons in all
there are 6 subshells.
There will be 2 sub shells .
4 s , p , d , 7
4 shells
7
4
no because f orbitals are not energetically available until the n=4 quantum state
Quantum numbers specify the orbitals in an atom. The set of numbers that cannot occur is n=3,I=3, m(sub)I=2 because there are no F-orbitals.
The principal quantum number, n, designates the main energy levels occupied by electrons. The number of orbitals in an energy level is n2 (n squared), so that the first energy level, n = 1, contains 1 orbital; the second energy level, n = 2, contains 4 orbitals; the third energy level, n= 3, has 9 orbitals; and the fourth energy level, n=4, has 16 orbitals, and so on.
Oxygen is in period 2 of the periodic table, telling you that it has n=2 or 2 orbits. The number of orbitals would be 1 in n=1 and 4 in n=2 for a total of 5 orbitals, if that is what you mean. Looking at it another way: for n=1, there is 1s (1 orbital); for n=2, there is 2s (1 orbital) and 2p (3 orbitals). The electron configuration is 1s2 2s2 2p4
2
16 orbitals
4
this is so bcoz neither F nor N has vacant orbitals(remember no d-orbitals)...whereas Cl in NCl3 has vacant d-orbitals to accomodate elctrons n get hydrolysed..
n=2 has 3 2p orbitals.
It depends which n since n is the row (period) number. 1st n = 1-s subshell, 1 orbital, and 2 electrons. 2nd n = 2-s subshell with 1 orbital and 2 electrons + 2-p subshell with 3 orbitals and 6 electrons.
no because f orbitals are not energetically available until the n=4 quantum state
principal energy level (n)= 3 Number of orbitals per level(n2)= 9 it equals 9 because it is n2 (32=9) n=1. 1 orbital n=2. 4 orbitals n=3. 9 orbitals n=4. 16 orbitals n=5. 25 orbitals n=6. 36 orbitalsn=7. 49 orbitals
Each shell has a total of n2 orbitals, where n is the principal quantum number. For N shells the total orbitals is therefore :- N2 + (N-1)2 + (N-2)2 +....+1
For fun, let's give them numbers instead of letters, and call s "0", p "1", d "2", and f "3".Then the number of distinct orbitals for any given principal quantum number (which is a more precise way of the concept you meant when you said "energy level") is twice the number plus 1... though the principal quantum number must be higher than the numbers we just gave the orbitals in order for there to be any at all (there aren't any 1p orbitals, for example). For principal quantum number of at least four, there are 1 s orbital, 3 p orbitals, 5 d orbitals, and 7 f orbitals. If we call the four quantum numbers n, l, m, and s, where n is the principal quantum number, l is the azimuthal quantum number, m is the magnetic quantum number, and s is the spin quantum number, the permissible values are: n - any integer such that 0 < n ("shell") l - any integer such that 0 <= l < n (orbital "type" - s, p ,d ,f, g, h, i, etc.) m - any integer such that -l <= m <= l (individual orbitals of type l) s - -1/2 or +1/2 (electron "spin")
24
in a "s" sublevel there are a max of 2 electrons located on 1 orbital. in a "p" sub level there are a max of 6 electrons located on 3 orbitals. in a "d" sub level there are a max of 10 electrons located on 5 orbitals. Extra: within a level (n=2 or n=3 etc) the number of orbitals (adding all the s, p, d etc) is n^2. so in a n=2 level, there are 4 orbitals (1 for 2s, 3 for 2p..1+3=4)