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To find the number of fluorine atoms in 5.59 g of C2F4, start by calculating the molar mass of C2F4: 12.01 g/mol (C) + 2(19.00 g/mol) (F) = 70.01 g/mol. Then divide the given mass by the molar mass to get the number of moles: 5.59 g / 70.01 g/mol ≈ 0.08 moles. Since there are 4 fluorine atoms in 1 molecule of C2F4, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then by 4 to get the number of fluorine atoms: 0.08 mol x 6.022 x 10^23 atoms/mol x 4 = approximately 1.93 x 10^23 fluorine atoms.

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