100% pure H2SO4 doesn't exist
Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------
I believe by using the Metric prefixes, 456. Cl is equal to 4560. Ml.
To calculate the number of moles in 76 grams of NaCl, you need to divide the given mass by the molar mass of NaCl. The molar mass of NaCl is approximately 58.5 g/mol. So, 76 grams of NaCl is equal to 76 g / 58.5 g/mol ≈ 1.30 moles.
456 cL is equal to 4560 mL, since there are 10 milliliters in 1 centiliter.
760mm Hg (standard atmospheric pressure) X .600=456 mm Hg
how many cups are in 456 g
456 L = 456 000 mLTo convert from L to mL, multiply by 1000.
456 grams
456
i think 4.5 grams
16.08 oz
there are 28.317 liters per cubic ft 38 X 12 = 456 For every 1 ft of depth (which you didn't supply) there are 12912.552 liters of water, or 28.317 X 456
Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------
This is an algebra problem. There will be 2 equations and 2 unknowns. Let x = amount of 7% solution, and y = amount of 19% solution. .07x + .19y = .15*456. x + y = 456; or x = 456-y which will substitute into the first equation. .07(456-y) +.19y = .15*456. 31.92-.07y+.19y = 68.4. .12y = 36.48. y = 304L (amount of 19% solution to add). x = 456-y. x = 456 - 304. x = 152L (amount of 7% solution to add).
456
There are: 456/6 = 76
To find out how many times 12 fits into 456, you can divide 456 by 12. The calculation yields 456 ÷ 12 = 38. Therefore, 12 goes into 456 a total of 38 times.