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Matter can not be created nor destroyed. So all of the carbon you begin with you will end up with in the end.
if you start with 1CH4 you have 1mol of C and 4 mol of H you will only be able to make 1mol of CO2 since each molecule of CO2 requires a Carbon atom.
What's most likely going on here is that you are burning CH4
CH4 + 2O2 --> CO2 + 2H2O
the H's end up in water molecules.
What else can I help you with?
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
How many grams of hydrogen are in 5.60 moles of methane?
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
Calculate the number of molecules given grams i.e how many molecules are there in 21.6 grams of CH4?
To calculate the number of molecules in 21.6 grams of CH4, you need to first determine the molar mass of CH4 (methane). The molar mass of CH4 is approximately 16 g/mol. Next, divide the given mass (21.6 g) by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
If 12.0 g of methane reacts completely with oxygen what is the final yield of CO2 in grams?
Since there is no limit on the amount of oxygen described in the question, you can assume that all the methane reacts with the oxygen. The reaction is CH4 + 2O2 --> CO2 + 2H2O The question asks for the amount of CO2 that is formed in grams so you need to know the soichiometric ratio between methane and carbon dioxide which in this case is 1:1. After that, it's just dimensional analysis. 12g CH4 X (1 mol CH4/16.032g) X (1mol CO2/1 mol CH4) X (44g CO2/1 mol CO2) = 32.93g of CO2 produced.
How many grams of CO2 are formed for every gram of CH4 that combusts?
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
How many hydrogen atoms are in 1.25 grams of CH4?
1,25 grams of CH4 contain 0,156696.10e23 atoms.
What number would you use to convert moles of CH4 to grams of CH4?
To convert moles of CH4 (methane) to grams, you would use the molar mass of CH4, which is approximately 16.04 g/mol. Multiply the number of moles of CH4 by this molar mass to obtain the mass in grams. The formula is: grams of CH4 = moles of CH4 × 16.04 g/mol.
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
How many moles in 64 grams of CH4?
There are 0.75 moles in it.You have to devide 12 by molecular mass
How many moles 64 grams of ch4?
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
How many grams of hydrogen are in 5.60 moles of methane?
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
How many grams of Al(OH)3 will be produced when 0.560 mol of CH4 is formed?
To find the number of moles of Al(OH)3 produced, we need to balance the chemical equation for the reaction where CH4 is formed. Once the equation is balanced, we can determine the mole ratio between Al(OH)3 and CH4. If we assume the balanced equation is: 4CH4 + 3O2 -> 2Al(OH)3 + 4H2O, we can see that the mole ratio is 2:4. Therefore, for every 2 moles of Al(OH)3 produced, 4 moles of CH4 are needed. Since we have 0.560 mol of CH4, we will produce half as many moles of Al(OH)3, which is 0.280 mol. To find the mass in grams, we can multiply the moles by the molar mass of Al(OH)3, which is 78 g/mol. Therefore, 0.280 mol of Al(OH)3 will be produced, which is equal to 21.84 grams.
How many moles of carbon dioxide is formed when 44mol of CH4 is burned?
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
How many moles of water H2O are produced from the reaction of 16 grams methane CH4 with an unlimited supply of oxygen O2. How many grams of H2O is this?
Two moles of water are produced.
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How much carbon dioxide does natural gas produce?
CH4 --> CO2 is a 1 to 1 reaction (C-balanced) when burning with oxygen. So 1 mole CH4 --> 1 mole CO2 So 1 Litere CH4 --> 1 Liter CO2 So 16 grams CH4 --> 44 grams CO2
