How many grams of NH3 are produced when 10.0g of H2 reacts with excess N2?

Answer 1

Step 1: balanced equation for the synthesis of ammonia:

N2 + 3H2 --> 2NH3

Step 2: convert 10g H2 to moles:

H2=2 g/mol; 10g = 5 moles of hydrogen.

Step 3: use molar ratios (coefficients) in balanced equation to determine moles of product:

3/2=5/x; solve for x to get 3.3 moles of ammonia (product).

Step 4: use relationship between moles and grams to get grams of product:

NH3=14+1+1+1=17 g/mol. Given 3.3 moles, 17(3.3)=56.1 grams NH3.