There are 192 grams of oxygen in 6 moles of O2.
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
There are 12 atoms in 6 O2 molecules.
2 oxygen,4 hydrogen, 4 hydrogen, and 2 oxygen so overall 12
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
The balanced chemical equation for the reaction between hydrogen and oxygen is: 2H2 + O2 -> 2H2O This equation shows that 1 mole of O2 reacts with 2 moles of H2. So, to completely react with 6 moles of H2, you would need 3 moles of O2.
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
the equation of this reaction is C + O2 = CO2 (s) (g) (g) according to this reaction 1mol of Carbon react with same number of moles of Oxygen. and this combination gives 1mol of CO2 as result. so first we have to find the number of moles in the weight we are going to use. 12 grams of carbon contains 1mol so 6 grams of carbon contains ( 1/12 )*6 = 0.5mol 32 grams of Oxygen contains 1mol 16 grams of Oxygen contains ( 1/36 )*16 = 0.5mol as 1mol of C react with 1mol of O2,0.5mol of C react with 0.5mol of O2. this produces equal number of moles (0.5mol) of CO2.
There are 12 atoms in 6 O2 molecules.
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
2 oxygen,4 hydrogen, 4 hydrogen, and 2 oxygen so overall 12
There are 6 grams are in 6 grams
The Lewis symbol for O2 is O=O, where each oxygen atom is represented by an O surrounded by 6 dots, indicating the 6 valence electrons of each oxygen atom.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
The subscript on an element indicates how many atoms of the element are present: ex: O2 - the 2 shows there are two oxygen's present C6H12O6(sugar)- there are 6 carbon 12 hydrogen and 6 oxygen
Oxygen is a diatomic gas, so a molecule of oxygen contains two oxygen atoms.One oxygen atom has an atomic weight of 16.00 amu (atomic mass units), so diatomic oxygen has a molecular weight of 16.00 × 2 or 32.00 amuamu (a.k.a., molar mass) are in units of grams/mol, so by dividing:8.0 g O2 ÷ 32.00 g/mol O2 = 0.25 mol O2One mol contains 6.022 × 1023 molecules (Avogadro's number), which can be multiplied by our 0.25 mol O2 to get the number of moles in 8.0 grams O2:0.25 mol O2 × (6.022 × 1023) = 1.5055 × 1023 moleculesDon't forget to round to two significant figures (limited in precision by the 8.0 grams given):There are 1.5 x 1023 molecules of O2 in 8.0 grams of O2
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The balanced chemical equation for the reaction between hydrogen and oxygen is: 2H2 + O2 -> 2H2O This equation shows that 1 mole of O2 reacts with 2 moles of H2. So, to completely react with 6 moles of H2, you would need 3 moles of O2.