How many grams of ethanol would be formed from the reaction of 0.250 kg of glucose?

Answer 1

.236

Answer 2

The conversion equation of glucose to ethanol is:

C{6}H{12}O{6} → 2C{2}H{5}OH + 2CO{2}

(Where numbers in braces {} should be in subscript which I can't do here)

Thus 1 mole of Glucose forms 2 moles of Ethanol.

1 mole of glucose weighs : 6×12 + 12×1 + 6×16 g = 180g

1 mole of ethanol weighs: 2×12 + 5×1 + 16 + 1 = 46 g

→ 180g of glucose makes 2×46 g = 92 g of ethanol

→ 0.250 kg glucose = 0.250 × 1000 g = 250 g

→ 0.250 kg glucose can produce 250 g ÷ 180 g × 92 g = 127 7/9 g ≈ 128 g of ethanol.

Answer 3

For each mole of glucose (180 g), 2 moles of ethanol (92 g) are produced in the fermentation reaction. You can calculate the number of moles of glucose in 0.250 kg and then use the stoichiometry to find the grams of ethanol produced.