To find the grams of F in 165 g of CaF2, you need to consider the molar mass of CaF2. Calcium (Ca) has a molar mass of about 40.1 g/mol, and fluorine (F) has a molar mass of about 19 g/mol. So, the molar mass of CaF2 is about 40.1 + (19 x 2) = 78.1 g/mol. Then, you can calculate the grams of F in 165 g of CaF2 by determining the proportion of F in the compound CaF2 compared to its total molar mass.
Fluorine, the element has a symbol/"formula" F. As a charged ion it has a -1 charge = F- Otherwise, fluorine is a diatomic molecule= F2 Calcium is also an element with symbol/"formula" Ca. As an ion it has a +2 charge, so it can be written as Ca2+.
The solubility product expression for CaF2(s) is written as Ksp = [Ca2+][F-]^2, where brackets denote the concentration of each ion at equilibrium.
165 degrees Celsius = 329 degrees Fahrenheit
The solubility product constant (Ksp) for CaF2 can be calculated using the formula Ksp = [Ca2+][F-]^2. Given the solubility of CaF2 is 0.00021 M, this means that [Ca2+] = 0.00021 M and [F-] = 0.00021 M as well. Therefore, Ksp = (0.00021)(0.00021)^2 = 9.261 x 10^-12.
The oxidation number of calcium (Ca) in CaF2 is +2. This is because fluorine (F) typically has an oxidation number of -1, and the overall charge of CaF2 is neutral. Since there are two fluorine atoms each with a -1 charge, the calcium atom must have a +2 oxidation number to balance the charges.
There are 284.7 grams of F.
Calcium fluoride, CaF2
165 degrees Fahrenheit = 73.89 degrees Celsius
Fluorine, the element has a symbol/"formula" F. As a charged ion it has a -1 charge = F- Otherwise, fluorine is a diatomic molecule= F2 Calcium is also an element with symbol/"formula" Ca. As an ion it has a +2 charge, so it can be written as Ca2+.
The reason it becomes stable is because Ca has 2 valence electrons that it wants to get rid of to become stable. F has 7 valence electrons and wants 1 more to become stable. So, TWO F atoms each take 1 of the 2 electrons from Ca. They form an ionic bond as Ca^2+ and 2F^- to make CaF2.
CaF2, Calcium Fluoride. It is useful in iron smelting
The solubility product expression for CaF2(s) is written as Ksp = [Ca2+][F-]^2, where brackets denote the concentration of each ion at equilibrium.
Ca+2 F-1 <----- these are the ions and their charges Ca+2 F-1 F-1 <----- the charges have to add up to zero, so two -1 fluorine ions cancel out one +2 calcium ions CaF2 <---- simplify
165 degrees Celsius = 329 degrees Fahrenheit
165 kelvin = -162.67 degrees Fahrenheit.[°F] = [K] × 9⁄5 − 459.67
Calcium fluoride is a binary compound.
The solubility product constant (Ksp) for CaF2 can be calculated using the formula Ksp = [Ca2+][F-]^2. Given the solubility of CaF2 is 0.00021 M, this means that [Ca2+] = 0.00021 M and [F-] = 0.00021 M as well. Therefore, Ksp = (0.00021)(0.00021)^2 = 9.261 x 10^-12.