There are 2.76 grams of nitrogen in 7.5g of Ca(NO3)2.
The correct formula for nitrogen trioxide is NO3.
Among the molecules NO, NO2, and NO3, NO3 will have the longest nitrogen-oxygen bond.
Among the molecules or ions NO, NO2, and NO3, the molecule with the strongest nitrogen-oxygen bond is NO3.
Nitrogen trioxide
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
The species is; Ca(NO3)2 ( NO3(-) is a polyatomic ion and is in parenthesis ) 7.5 grams Ca(NO3)2 (1 mole Ca(NO3)2/164.1 grams)(2 mole N/1 mole Ca(NO3)2)(6.022 X 10^23/1 mole N) = 5.5 X 10^22 atoms of nitrogen
There are a total of 3 nitrogen atoms in the formula Al(NO3)3.
Ca(NO3)2Number of atoms in the compound:Ca- 1N- 2O- 6Find the atomic masses of all atoms and add:Ca = 40.1N = 2 * 14.0 = 28.0O = 6 * 16.0 = 96.0___________________164.1 gEquation:# moles * added atomic mass = # gramsAnswer:4.2 moles * (164.1 g) = 689.22 grams of Ca(NO3)2
The correct formula for nitrogen trioxide is NO3.
Among the molecules NO, NO2, and NO3, NO3 will have the longest nitrogen-oxygen bond.
In each molecule of NO3, there is one nitrogen atom and there are three oxygen atoms.
Among the molecules or ions NO, NO2, and NO3, the molecule with the strongest nitrogen-oxygen bond is NO3.
Nitrogen trioxide
To determine the number of grams of Cu(NO3)2 produced, you need to consider the molar ratio between Cu(NO3)2 and Cu. Firstly, convert the 4.2 grams of Cu to moles using the molar mass of Cu. Then, use the balanced chemical equation to find the moles of Cu(NO3)2 produced. Finally, convert the moles of Cu(NO3)2 to grams using its molar mass.
N(nitrogen) = 7 electrons 3O(three oxygen) = 3* 8 electrons = 24 electrons 7 electrons + 24 electrons = 31 electrons in NO3 ( nitrogen trioxide ) ==============================
No lone pairs on the N in the nitrate anion (NO3^-)
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================