How many grams of oxygen does 0.5g of sulfur react with?

Answer 1

Firdt oh all qrite down the balanced reaction equation.

S(s) + O2(g) = SO2(g)

Note all the molar Ratios are 1:1 ::1

Next calculate the moles of sulphur

moles(S) = 0.5 / 32 = 0.015625 moles. (Equivalent to '1' ratio).

Moles(O2) = 0.015625 ( Equivalenbt to '1' ratio).

Hence mass of oxygen is

mass(g) = moles X Mr

Me( Relative Molecular Mass) of oxygen (O2) is 16 X 2 = 32

Hence mass = 0.015625 X 32 = 0.5 g (mass of oxygen(O2) required).

Answer 2

The answer to this 0.5grams of oxygen

Using the chemical equation S + 1/2O2 = SO2 (should be S8 + 8O2 = 8SO2)

Using the atomic masses 32.05 32

Therefore 32g of oxygen reacts with 32.06g of sulphur

Therefore 0.5g of oxygen reacts with (32.06/32) * 0.5g = 0.5g of oxygen

Hope this helps

Answer 3

If the reaction is between sulfur and oxygen in a 1:1 ratio, then 0.5g of sulfur would react with 0.5g of oxygen.