How many grams of potassium are in 24.1 g of K2Cr2O7?

Answer 1

The molecular weight of K2Cr2O7 is:

2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole

thus

24.1 g of K2Cr2O7 is 0.08192 moles.

Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)

Answer 2

To find the amount of potassium in K2Cr2O7, we need to determine the molar mass of K2Cr2O7 and the molar mass of potassium.

Molar mass of K2Cr2O7 = (239.10 g/mol) + (252.00 g/mol) + (7*16.00 g/mol) = 294.18 g/mol Molar mass of potassium = 39.10 g/mol

Now, determine the amount of potassium in 24.1 g of K2Cr2O7 by first converting 24.1 g of K2Cr2O7 to moles, then calculating the grams of potassium is in that amount of K2Cr2O7 using the molar ratios determined by the chemical formula.

Answer 3

24,1 g of K2Cr2O7 contain 6,39 g chromium.

Answer 4

Approx 9.9*10"22 atoms.