3 x 2 x 23 = 138g
6into23equals 138 6into23equals 138
106 grams
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O A+ = 234 grams
3 x 2 x 23 = 138g
6into23equals 138 6into23equals 138
3.121x10-5 Grams of Na2CO3
106 grams
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
My Shaft
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O A+ = 234 grams
234 grams :)
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
234 grams
The mass of sodium is 22,91.10e-23 g.