How many grams of solute are used in 270.0mL of 0.650M ethyl alcohol?

Answer 1

Use the moles equation.

moles = mass(g) / Mr = [conc]X vol(mL) / 1000

Algebraically eleiminating.

mass(g = Mr X [conc] x vol(mL)/1000

Ethyl Alcohol is Ethanol - CH3CH2OH ( Mr = 46)

Hence

mass(g) = 46 x 0,65 M X 270 mL / 1000

mass(g) = 8.073 g The answer!!!!

NB The '1000' is used to convert 'mL' to 'L' , because 'M - moles L^(=1).

Answer 2

The following solutions should be given so a person will be able to know how many grams of solute would be needed. With this information not given a person will not be able to know how much solute is needed.

Answer 3

steps.

change 270.0ml into litres, 270.0/1000L=0.27

moles of solute= molarity* litres

0.600M*0.27L=0.162

calculate molar mass of ethyl alcohol =46.06844

1 mole= 46.06844

0.162= ?

so, 46.06844*0.162= 7.46g

the answer is 7.46g

by: Hussein Abtidon,

from: Somalia

Answer 4

1. take 270.0 ml and convert into Liters

so, 270.0 ml/1000 ml = 0.270 Liters

2. Use Molarity equation to find your moles of solute. (M=moles/L)

so, change equation to moles=M*L 0.1755moles=(0.650M)*(0.270L)

3.now use molar mass to calculate grams (molar mass=moles/grams)

so, change equation to grams=(moles)/(molar mass)

0.000992grams=(0.1755moles)/(177molar mass)

Answer 5

To find the grams of solute, first calculate the moles of ethyl alcohol using the given concentration (0.650 mol/L) and volume (270.0 mL). Then, use the molar mass of ethyl alcohol (46.07 g/mol) to convert moles to grams. The calculation would be: 0.650 mol/L * 0.270 L * 46.07 g/mol = 7.05 grams of ethyl alcohol.