copper has 29 protons, when dealing with Cu^2+ all that means is it lost two electrons. so now the element has 29 protons and 27 electrons. Protons are positive and electrons are negative and neutrons are neutral. So say you had an element X^2- then you have gained two more electrons so the element has an overall negative charge. hope that helps
Copper (II) Bromide
Copper II bromide is considered ionic because it is composed of a metal (copper) and a nonmetal (bromine). Ionic compounds involve the transfer of electrons between the metal and nonmetal atoms, resulting in the formation of positively and negatively charged ions that are held together by electrostatic forces.
Copper (I) bromide. Unlike with a zinc compound question I just answered, the (I) here is pretty important; both copper (I) bromide and copper (II) bromide exist and are commercially available.
Chromium bromide.
Two compounds are known: - copper(I) bromide: CuBr - copper (II) bromide: CuBr2
Copper (II) Bromide
Copper(I) bromide is CuBr. Copper(II) bromide is CuBr2
Cu+2 Br-1
Copper II bromide is considered ionic because it is composed of a metal (copper) and a nonmetal (bromine). Ionic compounds involve the transfer of electrons between the metal and nonmetal atoms, resulting in the formation of positively and negatively charged ions that are held together by electrostatic forces.
Copper (I) bromide. Unlike with a zinc compound question I just answered, the (I) here is pretty important; both copper (I) bromide and copper (II) bromide exist and are commercially available.
Chromium bromide.
Two compounds are known: - copper(I) bromide: CuBr - copper (II) bromide: CuBr2
CuBr2 is often referred to as copper bromide. A more precise name is cupric bromide, which specifies that the copper is in the +2 state, and to distinguish it from cuprous bromide, with copper in the +1 state. It may also be written as copper (II) bromide.
copper (II) hypobromite
When copper(II) bromide reacts with sodium phosphate, a double displacement reaction occurs, resulting in the formation of copper(II) phosphate and sodium bromide. The balanced chemical equation for this reaction is: 3 CuBr₂ + 2 Na₃PO₄ → Cu₃(PO₄)₂ + 6 NaBr. The copper(II) phosphate may precipitate out of solution depending on the concentrations of the reactants. This reaction illustrates the exchange of ions between the two compounds.
The formula for copper (II) bromide is CuBr2. It consists of one copper (Cu) atom bonded to two bromine (Br) atoms.
Copper (II) bromide