1000 kg, since 1 g = 1 mL and thus 1000 kg = 1000 L.
It would be useful to know what grade of Acetic Acid you are using as differing grades have slightly different specific gravities. Based upon the specific gravity being 1.05, then 50 litres x 1.05 = 52.5kg
The normality of acetic acid in commercial vinegar that is 4% acetic acid is 0.84 N. This is calculated by multiplying the molarity of acetic acid by the number of acidic hydrogens in acetic acid. Since acetic acid has one acidic hydrogen, the normality is equal to the molarity.
One gallon of acetic acid weighs approximately 8.6 pounds or 3.9 kilograms.
(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
It would be useful to know what grade of Acetic Acid you are using as differing grades have slightly different specific gravities. Based upon the specific gravity being 1.05, then 50 litres x 1.05 = 52.5kg
The normality of acetic acid in commercial vinegar that is 4% acetic acid is 0.84 N. This is calculated by multiplying the molarity of acetic acid by the number of acidic hydrogens in acetic acid. Since acetic acid has one acidic hydrogen, the normality is equal to the molarity.
One gallon of acetic acid weighs approximately 8.6 pounds or 3.9 kilograms.
(.05)X(grams of total solution) = grams of acetic acid (grams of acetic acid)/ (mol. wt. of acetic acid(=60g/mol)) = mol. acetic acid (mol. acetic acid)/ (Liters of total solution) = molarity(M)
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
Vinegar contains about 5–20% acetic acid (CH3COOH), water and flavourings.
The molality of a solution is defined as the number of moles of solute per kilogram of solvent. First, convert the grams of water to kilograms. Then, calculate the molality using the formula: molality = moles of acetic acid / kilograms of water.
Yes. Acetic acid is a lot like acetic acid.
To prepare a 5000 PPM (parts per million) acetic acid solution, you would need to dissolve a specific amount of acetic acid (in grams) in a known volume of water (in liters). The formula to calculate the amount of acetic acid needed is: Mass of acetic acid (g) = volume of solution (L) x desired concentration (PPM) / 1000000.
No, acetic acid and acetic acid ester are not the same thing. Acetic acid is a simple organic compound with the chemical formula CH3COOH, while acetic acid ester is a compound formed by the reaction of acetic acid with an alcohol. Esterification of acetic acid forms esters, which are often used as fragrances or flavorings.
That is the condensed formula for the weak acid acetic acid.CH3COOH is a common formula for acetic acid written by biochemists and biologists
Acetic Acid or ethanoic acid {CH3COOH}.BEING ACID,IT TURNS BLUE LITMUS RED.IT IS SOUR.