The equation is straight forward. One mole will react with one mole. So how many moles are in 34ml of .113M BaCl2? 0.113 / 1000, x 34 is 0.003842 moles BaCl2. So we now need to find out how many ml of Na2SO4 is 0.003842 moles. dividing 0.218 by 1000 tells you the amount of moles in 1 ml. i.e. 0.000218 moles. 0.003842/0.000218 = 17.624 ml needed to react.
No, sodium sulfate does not react with aluminum. Sodium sulfate is a neutral salt and does not possess the capability to corrode or react with aluminum metal.
Copper bromide and sodium sulfate will react to form copper sulfate and sodium bromide. This is a double displacement reaction where the cations and anions switch partners.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
Copper bromide and sodium sulfate react to form copper sulfate and sodium bromide. This is a double displacement reaction where the positive ions of the two compounds switch places.
There would be no reaction because all possible outcomes are soluble in water, and if it did react your products would be the same as the reactants because you have sulfate on both of the reactants.
sodium carbonate and barium chloride react to form sodium chloride and barium carbonate Na2CO3 +BaCl2 -------> 2NaCl +BaCO3
No, sodium sulfate does not react with aluminum. Sodium sulfate is a neutral salt and does not possess the capability to corrode or react with aluminum metal.
Yes, they do react, to form Sodium sulfate and Water
Sodium hydroxide and sodium sulfate don't actually react.
When BaCl2 (barium chloride) is added to Na2SO4 (sodium sulfate), a precipitation reaction occurs, resulting in the formation of a white precipitate of barium sulfate (BaSO4). This is represented by the chemical equation: BaCl2 + Na2SO4 → BaSO4 + 2NaCl.
Yes. Ammonium sulfate reacts with sodium hydroxide to produce sodium sulfate, ammonia, and water. (NH4)2SO4 + 2NaOH --> Na2SO4 + 2NH3 + 2H2O
Copper bromide and sodium sulfate will react to form copper sulfate and sodium bromide. This is a double displacement reaction where the cations and anions switch partners.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
NaCl(s) + HNO3(g) ---------------- > NaNO3(s ) + HCl(g)
Copper bromide and sodium sulfate react to form copper sulfate and sodium bromide. This is a double displacement reaction where the positive ions of the two compounds switch places.
Yes, it is true. The equation of reaction is :- BaCl2 + Na2SO4 --------> 2NaCl(aq.) + BaSO4 where solution is of sodium chloride and Barium sulphate settles down at the bottom as precipitate
The reaction between barium chloride (BaCl₂) and sodium sulfate (Na₂SO₄) is a double displacement (or precipitation) reaction. In this reaction, the barium ions (Ba²⁺) react with sulfate ions (SO₄²⁻) to form barium sulfate (BaSO₄), which is insoluble and precipitates out of the solution. The sodium ions (Na⁺) and chloride ions (Cl⁻) remain in solution. This type of reaction is commonly used to demonstrate precipitation in chemistry.