How many many molecules are present in 4.25 mol of CCI4?

Answer 1

1 mole = (6.022 x 10^23)

So 4.5 moles = (4.5) x (6.022 x 10^23)

4.5 x (6.022 x 10^23) = 2.7099 × 1024

(four point five times six point zero two two times ten to the twenty third)

Answer 2

For carbon tetrachloride, CCl4: 5 atoms.

For tetraiodoethene, C2I4: 6 atoms.

Answer 3

There are approximately 2.57 x 10^24 molecules of CCl4 in 4.25 mol. This calculation is done by multiplying Avogadro's number (6.022 x 10^23 molecules/mol) by the number of moles given (4.25 mol).

Answer 4

1.3 x 10^23