1 microgram is equal to 0.001 milligram Therefore: 50 micrograms = 0.05 milligrams
Bronze is a metal alloy that contains primarily copper, most commonly also contains tin, but can also be made of othe elements such as phosphorous, manganese, aluminum, or silicon. Bronze is typically 88% Copper and 12% Tin.
More than 50 miles long!!!---------After some data (see the link below): from one ounce of gold we can obtain a wire (0,000 005 in diameter) long of 62 miles.Gold is the most ductile and malleable metal.
based on your assumed data: 4.0*10-11 gms/ml, 1000ml per L => 4.0*10-8 gms/L => 4.0*10-5 grams/1000L or 1 tonne 15.0*1019 L 4*15==60=6.0*101 1019 L *10-8 gms/L *101 => 19-8+1=12 adding powers Answer: 6.0 *1012 gms. or 6 *109Kgms = 6,000,000,000 kgms Your data may be showing too low a concentration of gold. "It's been estimated that there is a milligram of gold in a ton of seawater." One tonne (metric) tonne is 1000 litres. 4.0*10-5 grams/1000L = 4.0*10-2 milligrams/1000L = 0.04 milligrams/tonne The quote above, if correct is 1.0 milligrams/tonne or 25 times what you are showing. ----some clippings on amount of gold in seawater - I don't know if these are accurate-- There is a huge quantity of gold is seawater. But it's distributed widely - across all the oceans of all the world - and is incorporated on the atomic level. That makes it very, very hard to separate out. No one has demonstrated that it can be done economically. The concentration of gold in seawater varies from place to place, and ranges between 5 to 50 ppt (about .005 to .05 tonnes (5 to 50 kg) per km3) {It's been estimated that there is a milligram of gold in a ton of seawater.} Given that the volume of all the seas is about 1.37 billion km3 The total amount of gold in all the seas is about 7 to 75 billion kg. ------- Gold occurs in sea water to the extent of 0.1 to 2 mg/ton, depending on the location where the sample is taken. 1 cubic metre is equivalent to: * 1,000 litres -------------------- A cubic metre of pure water at the temperature of maximum density (3.98 °C) and standard atmospheric pressure (101.325 kPa) has a mass of 1000 kg, or one tonne.
Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
A whole lot! There is a huge quantity of gold is seawater. But it's distributed widely - across all the oceans of all the world - and is incorporated on the atomic level. That makes it very, very hard to separate out. No one has demonstrated that it can be done economically. The concentration of gold in seawater varies from place to place, and ranges between 5 to 50 ppt (about .005 to .05 tonnes (5 to 50 kg) per km3) Given that the volume of all the seas is about 1.37 billion km3 The total amount of gold in all the seas is about 7 to 75 billion kg.
005 = 5
.005 teaspoon is equal to approximately 0.00010416667 ounces.
No but 0.50 does
005 is not equal to 5 %; 0.05 is. 0.05 = 5/100 and "/100" is the same as "per cent".
Your figure 0.005 represents 005/100ths of a carat.
002+002+001=005
They are: .1+.02+.005 = .125
One half of a percent as a decimal is expressed as .005 Percent is out of 100 or 1 in most cases. 99 cents equal 1 dollar, so one HALF of ONE percent is .005 because one out of 100 = .01 so half of that would be .005 because .005 + .005 = .01
005 is thicker than 003
No. 5000 of most things (other than .005 metres) is not equal to 25 metres.
Half of 0.05 is 0.025
.005