A 1 M solution of glycerol indicates that there is 1 mole of solute per liter of solution. So in 1 liter, there is one mole, or 6.022 E 23 molecules.
Haha just had this on my take home bio quiz q 19. It is 6.02 x 10'23
6.02 x 10^23 aka 1 mole
Make Solution A by dissolving 174.18g of K2HPO4 in 1L of dH2O. Make solution B by dissolving 136g of KH2PO4 in 1L of dH2O. now mix solution A and B and finally adjust pH of your buffer.
the mass of the EDTA used to prepare 1L oi solution is 18.612g. The formula mass is 372.24 g/mol. Therefore concentration of the 50x solution is: 18.612 g 1 mol ----------- x --------- = 0.050000 mol/L = 50.000 mM 1L 372.24 g
1.34M--->1L xM---> 1.58 L = 1.34 x1.58 = 2.12 moles KCL
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
2g
1.3g
Make Solution A by dissolving 174.18g of K2HPO4 in 1L of dH2O. Make solution B by dissolving 136g of KH2PO4 in 1L of dH2O. now mix solution A and B and finally adjust pH of your buffer.
The solution to the Largo Winch latch puzzle is as follows: Key: 1-Ist latch from top R-Right 2-2nd latch from top L-Left 3-3rd latch from top 4-4th latch from top Solution: 1L-2L-1L-3L 1R-2R-1R-3L 1L-2L-1L-4L 1R-2R-1R-3R 1L-2L-1L-3R 1R-2R-1R-4L 1L-2L-1L-3L 1R-2R-1R-3L 1L-2L-3L
there are 1000 ml in 1l
the mass of the EDTA used to prepare 1L oi solution is 18.612g. The formula mass is 372.24 g/mol. Therefore concentration of the 50x solution is: 18.612 g 1 mol ----------- x --------- = 0.050000 mol/L = 50.000 mM 1L 372.24 g
1mL of water = 1cm3 but that conversion is dependent on water's density. If your solution was water in water (ha ha) then 1L = 1000 mL = 1000cm3 = 1 million mm3 (http://www.google.com/search?q=1L+to+cubic+mm) (http://www.google.com/search?q=1000cubic+cm+to+cubic+mm) You need to know the density of any "other" solution to accurately convert. If you meant "milliliters" then 1L = 1000mL, independent of density.
There are 1000 Ml. in a litre.
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
Gram percent is the number of grams of a solute per 100 grams of a solution. For example, if a solution of NaCl and water was said to have a 0.02g% of NaCl, this would mean that for 100g of saline solution, 0.02 of those grams are salt. Since 1L of water weighs 1kg (at normal conditions), there would be .2g of NaCl in 1L of a 0.02g% NaCl solution.
1L = 1000mL 600mL x 1L/1000mL = 0.6L
there are 1000mL in 1L