How many molecules are present in 4.25 mol of CCl4?

Answer 1

Each mole of C2H6O will have 6.022 E23 molecules present. That means that in 3.25 moles, there are 1.957 E24 molecules present.

Answer 2

There are approximately 1.02 x 10^24 molecules of CCl4 in 4.25 mol. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles.

Answer 3

Avogadro's constant says that in one mole there are 6.022 E23 instances of something. So in 4.25 moles, there are 2.56 E24 molecules of CCl4.

Answer 4

Full formal set up.

1 mole CCl4 (4 mole Cl/1 mole CCl4)(6.022 X 1023/1 mole Cl)(1 mole Cl atoms/6.022 X 1023)

= 4 moles Cl atoms

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Answer 5

1 mol of Cl2, weighs 70.1 g.

So 4.5 mol of Cl2 weighs 315.45 g

Answer 6

Multiply it by Avogadro constant. There are 7.5275*10^23 molecules

Answer 7

1 mole CO2 = 6.022 x 1023 molecules CO2

3.25mol CO2 x (6.022 x 1023 molecules CO2)/1mol CO2 = 1.96 x 1023 molecules CO2

Answer 8

3.25* (6.022* 10^23)= (1.96*10^24)

Answer 9

The answer is 3,683 molecules.

Answer 10

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