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# How many molecules are present in 4.25 mol of CCl4?

Updated: 8/10/2023

Wiki User

9y ago

Best Answer

Each mole of C2H6O will have 6.022 E23 molecules present. That means that in 3.25 moles, there are 1.957 E24 molecules present.

Wiki User

9y ago
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Wiki User

9y ago

Avogadro's constant says that in one mole there are 6.022 E23 instances of something. So in 4.25 moles, there are 2.56 E24 molecules of CCl4.

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Wiki User

11y ago

Full formal set up.

1 mole CCl4 (4 mole Cl/1 mole CCl4)(6.022 X 1023/1 mole Cl)(1 mole Cl atoms/6.022 X 1023)

= 4 moles Cl atoms

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Wiki User

11y ago

1 mol of Cl2, weighs 70.1 g.

So 4.5 mol of Cl2 weighs 315.45 g

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Wiki User

7y ago

Multiply it by Avogadro constant. There are 7.5275*10^23 molecules

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Wiki User

12y ago

1 mole CO2 = 6.022 x 1023 molecules CO2

3.25mol CO2 x (6.022 x 1023 molecules CO2)/1mol CO2 = 1.96 x 1023 molecules CO2

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Wiki User

11y ago

3.25* (6.022* 10^23)= (1.96*10^24)

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Wiki User

8y ago

The answer is 3,683 molecules.

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Wiki User

12y ago

15

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