There are 6.02x1023 atoms in one mole of any substance. This number is a constant known as Avogadro's number. Check it out on wikipedia here...http://en.wikipedia.org/wiki/Avogadro%27s_number. As far as calculating your answer, just multiply and don't lose track of your decimal places.
Mass V = 76 g moles V = 76/ 51 g/mol=1.5 moles O = 100 - 76/ 16= 1.5 VO Moles V = 68/51 = 1.3 Moles O = 100-68/16=2 1.3/1.3 = 1 =>V 2/1.3=1.5 =>O multiply by 2 to get whole numbers V2O3 moles V = 61/51=1.2 moles O = 100-61/16=2.4 VO2 moles V = 56/51=1.1 moles O= 100-56/16= 2.75 1.1/1.1= 1 => V 2.75/1.1= 2.5 =>O to get whole numbers multiply by 2 V2O5
108 - 47 = 61 neutrons 47 = atomic number of silver = number of protons
The number of protons in a atom is equal to the atomic number, therefor Ag has 47 protons. The number of protons and neutrons in an atom is equal to the atomic mass, therefor (108-47= 61) Ag has 61 neutrons. The number of electrons is equal to the number of protons therefor Ag has 47 electrons.
First calculate how many grams a mole of C6H12 weighs: Hydrogen is 1, and you have 12 hydrogens. Carbon is 6 and you have 6 carbons. So a mole weighs 1x12 + 6x6 = 48. Now multiply 48 x .61 and you have it. Final answer is in grams
There are about 61 neutrons in silver. It actually has less electrons and protons than neutrons, since it only has 47 of them.
62 grams a+
Mass V = 76 g moles V = 76/ 51 g/mol=1.5 moles O = 100 - 76/ 16= 1.5 VO Moles V = 68/51 = 1.3 Moles O = 100-68/16=2 1.3/1.3 = 1 =>V 2/1.3=1.5 =>O multiply by 2 to get whole numbers V2O3 moles V = 61/51=1.2 moles O = 100-61/16=2.4 VO2 moles V = 56/51=1.1 moles O= 100-56/16= 2.75 1.1/1.1= 1 => V 2.75/1.1= 2.5 =>O to get whole numbers multiply by 2 V2O5
The chemical equation is 2Al+3Br2 --> 2AlBr3 So find the number of moles of the aluminum and bromine. Moles of aluminum = 31 g Al/ 27 g/mol = 1.15 moles Moles of bromine = 97.5g/ 159.8 g/mol = .61 moles Then you find the limiting reagent by dividing the number of moles of each substance by their coefficient. 1.15 moles Al / 2 = .575 .61 moles Br / 3 = .203 That means that .203 *2 moles of AlBr3 was produced, because once the Br reactant runs out, the reaction stops and you cannot get anymore of the product. So .406 moles of AlBr3 multiplied by the molecular weight of AlBr3, 266.7 g/mol, yields 108.28 grams of AlBr3
61 inches.
There are 61 feet in 61 feet.
61
61 inches = 1.5494 meters.
61 altogether in June and July 31 +30 61
61 has 2 sig figs.
305/61 = 5
125 ÷ 61 = 2 with remainder 3.
A standard piano with 61 keys has 61 keys in total.