The number of molecules in 15 g ethane is approx. 3,011.10e23.
Ethane. Usually written C2H6.
The compound C2H8 is commonly called Butene or butylene.
C2H6 is called ethane. It is a hydrocarbon compound consisting of two carbon atoms and six hydrogen atoms.
The covalent name of C2H6 is ethane.
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
Ethane. Usually written C2H6.
The compound C2H8 is commonly called Butene or butylene.
124 grams of ethane is equal to 4,124 moles.
C2H6 is called ethane. It is a hydrocarbon compound consisting of two carbon atoms and six hydrogen atoms.
The covalent name of C2H6 is ethane.
Ethane is C2H6.
This term was initially used for ethane C2H6.
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
C2h6
No, C2H6 (ethane) is not an ionic compound. It is a covalent compound because it consists of nonmetals sharing electrons to form bonds. Ionic compounds are formed between metals and nonmetals through the transfer of electrons.
The balanced chemical equation for the oxidation of ethane (C2H6) to form water (H2O) and carbon dioxide (CO2) is: 2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O. This equation shows that two molecules of ethane react with seven molecules of oxygen to produce four molecules of carbon dioxide and six molecules of water.
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.