The number of molecules in 15 g ethane is approx. 3,011.10e23.
The compound C2H8 is commonly called Butene or butylene.
Ethane. Usually written C2H6.
Chlorocthase C2H2Cl Ethanec C2H6 Chloroethane, C2H5Cl Ethane, C2H6
Ethane is C2H6, with a molar mass of 30g/mol. 60g of ethane is 2mol. Avogadro's number (# of particles in a mole) = 6.02x1023. Avogadro x 2mol = 1.2x1024 ethane molecules.
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
The compound C2H8 is commonly called Butene or butylene.
This is the molecular formula of a compound named "ethane".
Ethane. Usually written C2H6.
124 grams of ethane is equal to 4,124 moles.
Chlorocthase C2H2Cl Ethanec C2H6 Chloroethane, C2H5Cl Ethane, C2H6
Ethane is C2H6, with a molar mass of 30g/mol. 60g of ethane is 2mol. Avogadro's number (# of particles in a mole) = 6.02x1023. Avogadro x 2mol = 1.2x1024 ethane molecules.
Ethane is C2H6.
This term was initially used for ethane C2H6.
The chemical formula for ethane is C2H6 and there is 6.022 * 10^23 molecules in every mole. So to find your answer simply multiply 6.022 * 10^23 by 51.2 which gives: 3.083 X 10^25
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.
C2h6
Ethane.