(0.33 moles) × (6.02×1023 molecules per mole) = 1.99×1023 molecules.
1.99×1023 molecules × 3 atoms per molecule = 5.96×1023 atoms
(0.33 moles) × (6.0221415 × 1023molecules per mole) = 1.987306695×1023 molecules.
1.987306695×1023 molecules × 3 atoms per molecule =5.961920085 1023 atoms
I would use the rounded answer, 5.96×1023 atoms
27.4 g H2O x 1 mole/18 g = 1.52 moles
6.00 g H2O x 1 mol H2O/18 g H2O = 0.333 moles of water present in 6.00 g of water. How anyone came up with 3.00 moles is a mystery.
The balanced chemical equation for the production of water from hydrazine is: 4N2H4(l) + O2(g) → 4H2O(g) + 4N2(g) From the equation, it can be seen that 4 moles of water are produced for every 1 mole of hydrazine. Therefore, if 14000 moles of hydrazine are used, 14000 moles of water will be produced.
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams.417 grams H2O / (18.0 grams) = .0232 moles H2O
To find the number of moles of water molecules in a 27 gram sample, you need to divide the mass by the molar mass of water (18.015 g/mol). 27 g / 18.015 g/mol = approximately 1.5 moles of water molecules.
6,00 g of water contains how 0,33 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles
6.00 g H2O x 1 mol H2O/18 g H2O = 0.333 moles of water present in 6.00 g of water. How anyone came up with 3.00 moles is a mystery.
10,55 moles of water are obtained.
10 moles of water (molar mass 18.0 g/mol) in 180 g, because 180 /18.0 = 10
This value is 0,06 moles.
1/18 = 0.0556
The mass of 0,5 moles of water is 9 g.
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
The molar mass of water (H2O) is approximately 18.02 g/mol. To find the number of moles in 40.0 g of water, you would divide 40.0 g by the molar mass of water. This would give you approximately 2.22 moles of water.
The balanced chemical equation for the production of water from hydrazine is: 4N2H4(l) + O2(g) → 4H2O(g) + 4N2(g) From the equation, it can be seen that 4 moles of water are produced for every 1 mole of hydrazine. Therefore, if 14000 moles of hydrazine are used, 14000 moles of water will be produced.
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams.417 grams H2O / (18.0 grams) = .0232 moles H2O