2.61 X 10^24 atoms of gold (1 mole Au/6.022 X 10^23)
= 4.33 moles of gold
To find the number of moles, divide the number of atoms by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. ( \frac{4.2 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} = 7 \text{ moles} ) Therefore, there are 7 moles of gold in 4.2 x 10^24 atoms.
The formula unit of gold is generally considered to be a single atom. Therefore, the answer is 5.6 X Avogadro's Number or about 3.4 X 1024.
6.02 x 10 ^23 It's the same number for 1 mol of anything.
(2.16x10^24 atoms) x ( 1 mole/ 6.022x10^23 atoms) = 0.3586848223x10^1 which your answer should be 3.59 moles
There are 2.26 x 10^24 silver atoms in 3.75 moles of silver. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mole) by the number of moles.
2,80 1024 atoms of silicon equals 0,465 moles.
The answer is 15,2 moles.
1,67.1024 argon atoms is equal to 2,773 moles.
56 moles × (6.02 × 1023) = 3.37 × 1024 atoms
2.26*1024
To find the number of moles, divide the number of atoms by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. ( \frac{4.2 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}} = 7 \text{ moles} ) Therefore, there are 7 moles of gold in 4.2 x 10^24 atoms.
The formula unit of gold is generally considered to be a single atom. Therefore, the answer is 5.6 X Avogadro's Number or about 3.4 X 1024.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
(2.16x10^24 atoms) x ( 1 mole/ 6.022x10^23 atoms) = 0.3586848223x10^1 which your answer should be 3.59 moles
6.02 x 10 ^23 It's the same number for 1 mol of anything.
12,4439 kg of gold contain 63,177 moles.
10.0 moles K2SO4 (6.022 X 1023/1 mole K2SO4) = 6.02 X 1024 atoms of potassium sulfate ==========================