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How many grams of O2 are in 15 moles of O2. with work shown?
15 moles O2 (32 grams/1 mole O2) = 480 grams
How many grams of oxygen form when each quantity of reactant completely reacts. 2 KClO3 (s) plus 2 KCl(s) 3O2 (g)?
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
How many grams are there in 2.047 moles of O2?
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
How many grams of CO2 are used when 6.5 g of O2 are produced?
For every 2 moles of O2 produced, 3 moles of CO2 are used in the reaction. So you need to calculate the moles of O2 produced first using its molar mass, then use the mole ratio to find the moles of CO2 used. Finally, convert the moles of CO2 to grams using its molar mass.
How many moles of oxygen are needed to react completely with 2.3 moles of H2S 2H2S plus 3O2 2SO2 plus 2H2O?
The balanced equation shows that 2 moles of H2S react with 3 moles of O2. Therefore, to react completely with 2.3 moles of H2S, you would need (3/2) x 2.3 moles of O2 which is equal to 3.45 moles of O2.
How many moles are in 64 g of oxygen?
4.80 grams O2 (1 mole O2/32 grams ) = 0.150 moles of O2
How many grams of oxygen are needed to react completely with 200.0 g of ammonia NH3?
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 3O2 → 2N2 + 6H2O. From the equation, we can see that 3 moles of O2 are needed to react with 4 moles of NH3. This means the molar ratio of O2 to NH3 is 3:4. First, calculate the number of moles of NH3 in 200.0 g: 200.0 g NH3 / 17.03 g/mol NH3 = 11.75 moles NH3 Now, calculate the number of moles of O2 needed using the molar ratio: 11.75 moles NH3 * (3 moles O2 / 4 moles NH3) = 8.81 moles O2 Finally, convert moles of O2 to grams: 8.81 moles O2 * 32 g/mol O2 = 282.0 g O2.
How many grams of O2 are in 15 moles of O2. with work shown?
15 moles O2 (32 grams/1 mole O2) = 480 grams
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
How many moles of O2 g are produced by the reaction of 156 g CO2 g with excess KO2?
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
How many grams of oxygen form when each quantity of reactant completely reacts. 2 KClO3 (s) plus 2 KCl(s) 3O2 (g)?
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
How many grams are in 0.800 moles of oxygen?
0,800 moles of oxygen (O2) is equivalent to 25,6 g.
What number of moles of o2(g) is required to react with 3.6 mole so2(g) in 2so2(g) o2(g) - 2so3(g)?
1,8 moles of oxygen are necessary.
How many grams of o2 are required to produce 90g of no?
2 moles of nitrogen monoxide (NO) are produced from 1 mole of oxygen (O2) according to the balanced chemical equation 2NO = N2 + O2. One mole of NO has a molar mass of 30 g, so 90 g of NO corresponds to 3 moles of NO. Therefore, 3 moles of O2 are required to produce 90 g of NO, which is equivalent to (3 moles) x (32 g/mol) = 96 g of O2.
How many moles of O2 are needed to burn 1.35mol of C8H18?
16,875 moles of oxygen are needed.
How many grams are there in 2.047 moles of O2?
For this you need the atomic (molecular) mass of O2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.047 moles O2 × (32.0 grams) = 65.5 grams O2
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
