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Find the mass(in grams) of potassium permanganate, KMnO4, present in 500 ml of a 3.00 M solution.

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Danielle Lopez

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4y ago

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What mass of KMnO4 is required to prepare 3.00 liters of a 0.05253 M solution of KMnO4?

To find the mass of KMnO4 needed, you can use the formula: mass = molarity x volume x molar mass. First, calculate the moles of KMnO4 using moles = molarity x volume. Then, multiply the moles by the molar mass of KMnO4 to find the mass needed.


A certain amount of hydrogen peroxide was dissolved in 100 ml of water and then titrated with 1.68m kmno4 how much h2o2 was dissolved if the titration required 22.3 ml of the kmno4 solution?

To calculate the amount of hydrogen peroxide (H2O2) dissolved, you can use the equation: moles of KMnO4 = moles of H2O2. Firstly, calculate the moles of KMnO4 (given concentration and volume). Then, use the balanced chemical equation to determine the moles of H2O2, as they have a 1:1 stoichiometric ratio. Finally, convert moles of H2O2 to grams using the molar mass to find the amount dissolved in the solution.


How can one determine the number of moles present in a solution by using the molarity and volume of the solution?

To determine the number of moles in a solution, multiply the molarity (in moles per liter) by the volume of the solution (in liters). This calculation gives you the amount of substance in moles present in the solution.


How many grams of potassium permanganate KMnO4 are in 2.55 moles?

The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g


How do you find molar concentration of chemical compounds?

By applying the formula: No. of moles = Mass of compound / Molar Mass of compound eg: We have to find concentration of KMnO4,so ; No.of moles of KMno4 = Mass of KMnO4 / Molar mass of KMnO4


How many moles are in 100g of KMnO4?

1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g


How can one determine the number of moles present in a solution by utilizing the concentration and volume measurements?

To determine the number of moles in a solution, you can use the formula: moles concentration x volume. Simply multiply the concentration of the solution (in moles per liter) by the volume of the solution (in liters) to find the number of moles present.


What volume of 0.380 M NaI would be required to oxidize 45.0 ml of 0.500 M KMnO4 in acidic solution?

To determine the volume of 0.380 M NaI needed to oxidize 45.0 mL of 0.500 M KMnO4 in acidic solution, we first calculate the moles of KMnO4: [ \text{Moles of KMnO4} = 0.500 , \text{M} \times 0.045 , \text{L} = 0.0225 , \text{moles} ] In acidic conditions, the balanced reaction shows that 1 mole of KMnO4 reacts with 5 moles of I⁻ (from NaI). Therefore, the moles of NaI required are: [ \text{Moles of NaI} = 5 \times 0.0225 = 0.1125 , \text{moles} ] Now, using the concentration of NaI, we can find the volume needed: [ \text{Volume of NaI} = \frac{0.1125 , \text{moles}}{0.380 , \text{M}} \approx 0.296 , \text{L} \text{ or } 296 , \text{mL} ] Thus, approximately 296 mL of 0.380 M NaI is required.


The molarity of a solution refers to?

The molarity of a solution refers to the concentration of a solute in moles per liter of solution. It is a measure of how many moles of solute are present in a given volume of the solution.


What is the molarity of 0.1 normal KMnO4?

The formula mass of KMnO4 is 158.0Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 molThere are 0.633 moles in 100g of potassium permanganate.


How many mols in 100g of KMnO4?

0.006327754


When a titration is complete what two things are equal?

In a titration, the moles of the titrant added are equal to the moles of the analyte in the solution. At the endpoint, the moles of the titrant consumed are equal to the moles of the analyte present in the solution.