How many moles of N2O3 contain 2.55 x 1024 oxygen atom?

Answer 1

To determine the number of moles of N2O3 containing 2.55 x 10^24 oxygen atoms, we first calculate the molar mass of N2O3, which is 76.01 g/mol. Next, we find the number of moles of oxygen atoms in 2.55 x 10^24 atoms by dividing the given number by Avogadro's number (6.022 x 10^23 atoms/mol). This gives us approximately 4.24 moles of oxygen atoms. Since each mole of N2O3 contains 3 moles of oxygen atoms, the number of moles of N2O3 containing 2.55 x 10^24 oxygen atoms is 4.24 moles / 3 = 1.41 moles.

Answer 2

To find the number of moles of N2O3 containing 2.55 x 10^24 oxygen atoms, we first determine the number of moles in 2.55 x 10^24 oxygen atoms by dividing by Avogadro's number (6.022 x 10^23). This gives us the number of moles of O atoms. Since one mole of N2O3 contains 3 moles of oxygen atoms, we can then convert moles of O atoms to moles of N2O3 by dividing by 3.

Answer 3

2.55 X 1024 oxygen atoms ( 1 mole O /6.022 X 1023)(1 mole N2O3/3 mole O)

= 1.41 moles dinitrogen trioxide

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