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Assuming that you are combining the P4 with Cl2 and there is a suffiecient quantity of Cl2 for the P4 to completely react, you will first need a balanced equation which is P4 + 10Cl2 -> 4PCl5. From there, it's mostly stoichiometry. Take the 24g of P4, divide by the molar mass (123.88g/mol) to get the number of moles of P4 that you have (0.194). You then have to convert, using the balanced equation, from moles of P4 to moles of PCl5, in this case multiplying by 4. That will give you the number of moles of PCl5. The stoichiometry should look something like this 24.0 g P4 x (1 mol P4/123.88g P4) x (4 mol PCl5/1 mol P4).
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How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
How many moles of aluminum are produced from 33 grams of aluminum?
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
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114,426 g carbon dioxide are produced.
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How many moles of PCl5 can be produced from 56.0g Cl2 and excess P4?
To find out how many moles of PCl5 can be formed from the reaction of P4 and Cl2, it is necessary to set up the stoichiometric equation. X P4 + Y Cl2 --> Z PCl5. Balancing the equation, X = 1, Y = 10, and Z = 4. This means that for every mole of P4 that reacts, 4 moles of PCl5 is produced. The next step is to find out how many moles of P4 are present in 30.0 grams. The molar mass of P4 is 123.895 g/mol, so there are .24214 moles of P4 present. Multiplied by 4, the answer is 0.96856 moles of PCl5 are produced.
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How many moles of carbonic acid will be produced by the three grams of sodium carbonate?
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How many moles of PCl5 can be produced from 55.0 g of Cl2 (and excess P4)?
55.0 g of Cl2 contains 55.0/35.45* or 1.551 gram atoms of chlorine. Each mole of PCl5 requires exactly 5 gram atoms of chlorine, as shown by the formula. Therefore, 1.551/5.000 or 0.310 moles of PCl5 can be formed, to the justified number of significant digits. *This number is the gram Atomic Mass of chlorine.
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The mass of ammonia will be 95,03 g.
How many grams of CO2 are produced from 5 moles O2?
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
How many grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene C2H2?
114,426 g carbon dioxide are produced.
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16 grams of oxygen how many moles is 0,5 moles.
How many moles of NH3 are produced when 1.2 moles H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of PCl5 are in 35.6 g of PCl5?
Molar mass = 31+ 5(35.5) = 208.5 g/mole divide ... 35.6 g / 208.5 g/mole = 0.171 mole
How many grams of calcium phosphate are theoretically produced if you start with 10.3 moles of CaNO32 and 7.6 moles of Li3PO4?
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