How many moles of atoms are present in 6.4 moles os NaHCO3?

Answer 1

By definition, a mole of any substamce contains 6.022142 x 1023 molecules. This constant, known as the Avogrado constant, is how we convert atomic weight to grams. If you know the atomic weight of, say, oxygen is 15.9994, then one mole of oxygen weighs 15.9994 grams. Anyway, one mole of NaHCO contains 6.022142 x 1023 molecules, but each molecule contains four atoms (one each of Sodium, Hydrogen, Carbon, and Oxygen). So the total number of atoms in a mole of NaHCO is 4 x 6.022142 x 1023 = 2.408857 x 1024.

Answer 2

NaHCO3 is made of 6 atoms- 1xNa, 1xH, 1xC, 3xO. As such, 6.4 moles of NaHCO3 will contain 6.4 times this number of atoms, 6x6.4, 38.4 moles of individual atoms (6.4 of Sodium, 6.4 of Hydrogen, 6.4 of Carbon and 19.2 moles of Oxygen).

Answer 3

In 1 mole of NaHCO3, there is 1 mole of sodium (Na), 1 mole of hydrogen (H), 1 mole of carbon (C), and 3 moles of oxygen (O) atoms. Therefore, in 6.4 moles of NaHCO3, there would be 6.4 moles of sodium, 6.4 moles of hydrogen, 6.4 moles of carbon, and 19.2 moles of oxygen atoms.

Answer 4

Since the formula unit for Na is the single atom, 6.0 X Avogadro's number or 3.6 X 1024 atoms, to the justified number of significant digits.