moles = mass (g) divided by the molecular weight (g/mol)
moles = 100g/12.01
Mass of C= 80.0 g Mass of H =20.0 g
0.006327754
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
The half-life of the radioisotope is 9 years. This is calculated by determining the time it took for half of the original sample to decay. Since the sample went from 100g to 25g in 18 years, it lost 75g in that time period. After the first half-life, the sample would have 50g remaining, and after the second half-life, it would have 25g remaining.
Mass of C= 80.0 g Mass of H =20.0 g
To find the number of moles of Fe in Fe2O3, first calculate the molar mass of Fe2O3 and O. Then, determine the number of moles of O in the sample. Finally, you can use the stoichiometry of Fe2O3 to find the moles of Fe present. Alternatively, if you know the molar mass of just Fe, you can calculate the moles of Fe by dividing the mass of Fe in the sample by its molar mass.
0.006327754
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
100g=$2.40
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
the atomic mass of gallium is approximately 69.72 g/mol therefore the mass of 100 grams of gallium would be 100g divided by 69.72g/mol which gives us approximately 1.43 moles
To determine the grams of calcium carbonate needed, we first calculate the moles of carbon dioxide using the ideal gas law. At STP, 1 mole of any ideal gas occupies 22.4 L. Therefore, 49.0 L of carbon dioxide is 49.0/22.4 moles. From the balanced chemical equation, we know that 1 mole of calcium carbonate produces 1 mole of carbon dioxide. Finally, using the molar mass of calcium carbonate, we can convert moles to grams.
20 years (APEX)
The half-life of the radioisotope is 9 years. This is calculated by determining the time it took for half of the original sample to decay. Since the sample went from 100g to 25g in 18 years, it lost 75g in that time period. After the first half-life, the sample would have 50g remaining, and after the second half-life, it would have 25g remaining.
The chemical formula for limestone is CaCO3. When heated, limestone decomposes to produce calcium oxide (CaO) and carbon dioxide (CO2). The molar mass of CaCO3 is 100.09 g/mol. To calculate the mass of CO2 produced, you would first calculate the moles of CaCO3 in 2.00g, then use the stoichiometry from the balanced chemical equation to determine the moles and then mass of CO2 produced.
450 g water 100g sugar 30g vinegar 2g salt for vinegar use2.4 g of acetic acid