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A compound is 80.0 carbon and 20.0 hydrogen by mass Assume a 100g sample of this compound How many grams of each element are in this sample?
Mass of C= 80.0 g Mass of H =20.0 g
How many mols in 100g of KMnO4?
0.006327754
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
What is the half life of a radioisotope if a 100g sample becomes 25g after 18 years?
The half-life of the radioisotope is 9 years. This is calculated by determining the time it took for half of the original sample to decay. Since the sample went from 100g to 25g in 18 years, it lost 75g in that time period. After the first half-life, the sample would have 50g remaining, and after the second half-life, it would have 25g remaining.
A compound is 80.0 carbon and 20.0 hydrogen by mass Assume a 100g sample of this compound How many grams of each element are in this sample?
Mass of C= 80.0 g Mass of H =20.0 g
How many moles Fe are in a sample of Fe2O3 that contains 100g O?
To find the number of moles of Fe in Fe2O3, first calculate the molar mass of Fe2O3 and O. Then, determine the number of moles of O in the sample. Finally, you can use the stoichiometry of Fe2O3 to find the moles of Fe present. Alternatively, if you know the molar mass of just Fe, you can calculate the moles of Fe by dividing the mass of Fe in the sample by its molar mass.
How many mols in 100g of KMnO4?
0.006327754
How many moles are in 100g of KMnO4?
1 mol = 118.94 1 mol / 118.94 = 1.70 / x G = 202.10g
What is the cost of carbon?
100g=$2.40
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
What is the mass of 100g of ga?
the atomic mass of gallium is approximately 69.72 g/mol therefore the mass of 100 grams of gallium would be 100g divided by 69.72g/mol which gives us approximately 1.43 moles
How many grams of calcium carbonate are needed to produce 49.0 L of carbon dioxide at STP?
To determine the grams of calcium carbonate needed, we first calculate the moles of carbon dioxide using the ideal gas law. At STP, 1 mole of any ideal gas occupies 22.4 L. Therefore, 49.0 L of carbon dioxide is 49.0/22.4 moles. From the balanced chemical equation, we know that 1 mole of calcium carbonate produces 1 mole of carbon dioxide. Finally, using the molar mass of calcium carbonate, we can convert moles to grams.
What is the half life of a radioisotope if a 100g sample becomes 50 g after 20 years?
20 years (APEX)
What is the half life of a radioisotope if a 100g sample becomes 25g after 18 years?
The half-life of the radioisotope is 9 years. This is calculated by determining the time it took for half of the original sample to decay. Since the sample went from 100g to 25g in 18 years, it lost 75g in that time period. After the first half-life, the sample would have 50g remaining, and after the second half-life, it would have 25g remaining.
What mass of carbon dioxide would be produced when 2.00g of limestone is heated?
The chemical formula for limestone is CaCO3. When heated, limestone decomposes to produce calcium oxide (CaO) and carbon dioxide (CO2). The molar mass of CaCO3 is 100.09 g/mol. To calculate the mass of CO2 produced, you would first calculate the moles of CaCO3 in 2.00g, then use the stoichiometry from the balanced chemical equation to determine the moles and then mass of CO2 produced.
A hydrate is found to have the following percent composition 48.8 percent MgSO4 and 51.2 percent H2O What is the formula and name for this hydrate?
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
