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Fe3O4 is not a pure compound...it is a mixture of FeO and Fe2O3

Assuming 100% yield in converting to all Fe2O3

4.05 mole x 2/3 = 2.7 mole

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12y ago

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Related Questions

How many moles of Fe3O4 are needed to prepare 4.74 moles of Fe2O3?

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To calculate the weight of Fe3O4 needed to furnish 0.5430g of Fe2O3, you need to consider the molar masses of Fe3O4 and Fe2O3. The molar mass of Fe3O4 is 231.535 g/mol, and of Fe2O3 is 159.69 g/mol. By using the molar ratios between Fe3O4 and Fe2O3, you can determine that 0.5430g of Fe2O3 would require 0.7799g of Fe3O4.


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