How many moles of ions are in 27.5 g of MgCl2?

Answer 1

This is a trick question. There are no ions in MgCl2, the ions are bonded together, suspended in a solid. In the case of MgCl2 this is a white power.

Answer 2

To find the moles of ions in MgCl2, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass (27.5 g) by the molar mass to find the number of moles of MgCl2. Since there are three ions in one formula unit of MgCl2 (1 Mg ion and 2 Cl ions), multiply the moles of MgCl2 by 3 to find the moles of ions.

Answer 3

One mole of calcium carbonate, CaCO3 weighs 100 units. For our case we can say that there is 100g of CaCO3 in one mole of the substance. 27.5/100 yields 0.275 moles.

Answer 4

n=m/M

MMgCl2=(24,30+35,45*2)g/mol = 95,2g/mol

n=15g/95,2g/mol = 0,158mol

Answer 5

29/95 = 0.31 mol

Answer 6

0.898 mol

Answer 7

.293 MOLES