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Q: How many moles of iron atoms are there in 56g of iron?

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It depends on the RMM (relative molecular mass) of the molecule your dealing with. For example if you had 2 Moles of ethene (C2H4) then you would simply multiply the number of moles by the RMM, which for ethene is approximately 28 [2C=24 +4H=28] So just multiply the RMM (28) by the number of moles(2) which gives 56g so 2 Moles of C2H4 weighs 56g.

This is a mass stoichiometry problem. Start with the balanced equation: CaCO3 --> CaO + CO2. Do a conversion from 50g CaO to moles: 56g/1mol=50g/x, x=.9 moles. The equation is balanced as written, with all coefficients understood to be 1. So: .9 moles CaO means .9 moles CaCO3. Do another conversion from moles to grams: 100g/1mol=x/.9 moles. Solve for x to get 90 grams. (56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)

M(Cu)=64g/mol, M(Fe)=56g/mol, so Iron has greater volume.

Well, I ran the numbers for what you have in the question, and it didn't make sense, so I'm assuming you really mean 65g of iron yields 33g iron oxide. I'm also assuming you mean iron(III) oxide, which is iron's most common valence state when it reacts with oxygen, which means the product's formula would be Fe2O3.With those things in mind, here's your balanced equation:4Fe + 3O2 --> 2Fe2O3.Step1: given 65g Fe, how many moles is that? Direct proportion between 65g and the unknown # of moles and iron's atomic mass of 56g/mol gives us 1.16 moles of iron.Step 2: molar ratio of iron to iron(III) oxide is 4-2, which simplifies to 2-1, so you will have 0.58 moles of product.Step 3: given 0.58 moles of product, set up another direct proportion with the unknown mass over given moles equal to iron(III) oxide's molar mass of 160g/mol to get a mass of 92.8g theoretical yield of product.Step 4: your actual yield was 33g, so divide that by the stoichiometric yield of 92.8g, which is 0.355, which means about a 36% actual yield, which is the answer.

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Related questions

Molar mass of iron is 56g. Given mass of iron= 112g No. of moles = Given mass/Molar Mass => 112g/56g= 2 moles

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1.00274 moles

One mole of iron atom weighs 56g

This is carbon tetra chloride. there are 0.3636 moles in this mass.

There are more atoms of sulfur in 16 grams than there are atoms of iron in 56 grams.

It depends on the RMM (relative molecular mass) of the molecule your dealing with. For example if you had 2 Moles of ethene (C2H4) then you would simply multiply the number of moles by the RMM, which for ethene is approximately 28 [2C=24 +4H=28] So just multiply the RMM (28) by the number of moles(2) which gives 56g so 2 Moles of C2H4 weighs 56g.

56g=0.56kg

This is a mass stoichiometry problem. Start with the balanced equation: CaCO3 --> CaO + CO2. Do a conversion from 50g CaO to moles: 56g/1mol=50g/x, x=.9 moles. The equation is balanced as written, with all coefficients understood to be 1. So: .9 moles CaO means .9 moles CaCO3. Do another conversion from moles to grams: 100g/1mol=x/.9 moles. Solve for x to get 90 grams. (56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)

M(Cu)=64g/mol, M(Fe)=56g/mol, so Iron has greater volume.

130% of 56g = 130% * 56 = 1.3 * 56 = 72.8g

One bag of skittles has 56g of carbs.

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