How many moles of magnesium a chloride are produced when a 4.3 grams piece of magnesium is placed in a bottle of hydrochloric acid large enough to completely react with the magnesium?

Answer 1

First of all write down the BALANCED reaction equation.

Mg(s) + 2HCl(aq) = MgCl2(aq) + H2(g)

We note that the molar ratios are 1:2::1:1

Next calculate the moles of Mg

mol(Mg) = 4.3 / 24.3 (Atomic Mass)

mol(Mg) = 0.17695...

Hence by equivalence with the mole ratios

0.17695... moles of MgCl2 are produced.

NB

1:2::1:1 becomes 0.17695 , 0.353909...:: 0.17695...:0.17695...

695... : 0.

Answer 2

The chemical equation for the reaction between magnesium and hydrochloric acid is: Mg + 2HCl -> MgCl2 + H2. To find the moles of magnesium chloride produced, first calculate the moles of magnesium reacting using its molar mass. Then, since the ratio between magnesium and magnesium chloride is 1:1, the number of moles of magnesium chloride produced will be the same as the moles of magnesium reacting.

Answer 3

Mg + 2HCl --> MgCl2 + H2

4.3g Mg x 1 mol Mg/24.30g x 1 mol MgCl2/1 mol Mg = 0.18 mol MgCl2