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Mg2+(s) + 2HNO3(l)= Mg(NO3)2(aq) + H2(g)

since the only mole value given is 8 I must assume this is the limiting reactant.

Because of the 2:1 ratio of Nitric acid to Magnesium Nitrate, meaning there must be 2 moles Nitric acid for every 1 mole Magnesium Nitrate formed, 4 moles of Magnesium nitrate will be formed.

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Q: How many moles of magnesium nitrate are produced when magnesium reacts with 8 moles of nitric acid?
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