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How many moles of hydrogen gas contained in 9.03x1023?
Given/Known:1mole of H2 = 2.01588g H21mole of H2 = 6.022 x 1023 molecules H21) Convert molecules of H2 to moles of H2 by doing the following calculation.9.4 x 1025 molecules H2 x (1mol H2/6.022 x 1023 molecules H2) = 156mol H22) Convert the moles of H2 to mass in grams of H2.156mol H2 x (2.01588g H2/1mol H2) = 314g H2
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many molecules (not moles) of NH3 are produced from 5.95104 g of H2?
The number of ammonia molecules is 59 720.10e23.
How many molecules -not moles- of NH3 are produced from 3.07104 g of H2?
Balanced equation is N2 + 3H2 ==> 2NH33.07104 g H2 x 1 mol/1.0079 g = 1.7679 moles H2 presentmoles NH3 produced = 2/3 x 1.7679 moles = 1.1786 moles NH3 formedmolecules NH3 = 1.1786 moles x 6.022x10^23 molecules/mole = 7.098x10^23 molecules (4 sig figs based on sig figs used in 6.022x10^23)
How many molecules are in a 2 mole sample of hydrogen?
1 mole of H2 has 6.023 x 1023 molecules So, 2 moles will have 12.046 x 1023 molecules
calculate the number of moles in H2 molecules in 4g H2?
2 moles.
How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?
The answer is 1,57.10e27 molecules.
How many moles of hydrogen gas contained in 9.03x1023?
Given/Known:1mole of H2 = 2.01588g H21mole of H2 = 6.022 x 1023 molecules H21) Convert molecules of H2 to moles of H2 by doing the following calculation.9.4 x 1025 molecules H2 x (1mol H2/6.022 x 1023 molecules H2) = 156mol H22) Convert the moles of H2 to mass in grams of H2.156mol H2 x (2.01588g H2/1mol H2) = 314g H2
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many molecules of H2 are present in 0.175 moles of H2?
0.175 X Avogadro's Number = about 1.05 X 1023.
How many molecules (not moles) of NH3 are produced from 5.95104 g of H2?
The number of ammonia molecules is 59 720.10e23.
What is the mass of 4 moles of hydrogen molecules (H2)?
8.086g
How many ATOMS are in a tank containing 10 moles of gaseous H2 molecules?
12.044x10^[24] atoms
How many moles of NH3 can be produced from 2.37x10-4 moles of H2?
First we are going to find number of H2 moles form it mass H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles Since 3 moles of H2 makes 2 moles of NH3 then by using this ration, we can find number of moles in NH3 NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23). #NH3 molecules = (0.79*10^-4) *(6.022*10^23) =4.75 * 10^19 molecules of NH3 Good luck Enas
How many molecules -not moles- of NH3 are produced from 3.07104 g of H2?
Balanced equation is N2 + 3H2 ==> 2NH33.07104 g H2 x 1 mol/1.0079 g = 1.7679 moles H2 presentmoles NH3 produced = 2/3 x 1.7679 moles = 1.1786 moles NH3 formedmolecules NH3 = 1.1786 moles x 6.022x10^23 molecules/mole = 7.098x10^23 molecules (4 sig figs based on sig figs used in 6.022x10^23)
How many molecules are in a 2 mole sample of hydrogen?
1 mole of H2 has 6.023 x 1023 molecules So, 2 moles will have 12.046 x 1023 molecules
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
