The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.
Balanced equation:
C3H8 + 5O2 --> 3CO2 + 4H2O
Each mole of propane will require 5 moles of oxygen for complete combustion.C3H8 + 5O2 ==> 3CO2 + 4H2O
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
4 moles of oxygen atoms are present in 4 moles of H2O
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.
The answer is: 5 moles oxygen and 4 moles H2O.The reaction is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
30 moles
Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.
5.8
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
.913 moles
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
999 g