3.5
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
10 grams of calcium carbide can produce approximately 4.4 liters of acetylene gas at standard conditions (STP). This is calculated based on the stoichiometry of the reaction between calcium carbide and water to produce acetylene gas.
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
To find the volume of the dry gas at standard conditions (0°C and 1 atm), we need to correct for the water vapor using the vapor pressure of water at 20°C. The vapor pressure of water at 20°C is 17.5 mm Hg. Therefore, the pressure of the dry gas is 622.0 mm Hg (total pressure) - 17.5 mm Hg (water vapor pressure) = 604.5 mm Hg. Using the ideal gas law, we can calculate the volume of the dry gas at standard conditions.
The maximum volume of gas that can be stored in a standard gas cylinder is typically around 50 liters.
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There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
Standard Liter per minute (SLPM) refers to the flow rate of a gas at "standard conditions" (usually sea level pressure, room temperature..etc) Liter per minute (LPM) is the flow rate at the conditions being measured. This is an important distinction when measuring compressed gasses. One liter of compressed gas will expand to a higher volume at standard conditions.
The number of moles of helium is 0,32.
"Lpm" stands for liters per minute, while "slpm" stands for standard liters per minute. Standard liters are measured at a specific set of conditions, typically at standard temperature and pressure (STP). The difference between lpm and slpm is that slpm takes into account the variations in gas density that can occur due to changes in temperature and pressure.
To produce 67.3 L of CO at standard conditions, you would need 67.3 grams of oxygen. This is because the molar ratio of oxygen to carbon monoxide in the reaction is 1:1. At standard conditions, 1 mole of any gas occupies 22.4 liters.
At standard temperature and pressure (STP), one mole of any ideal gas occupies 22.4 liters. To find the number of moles of ammonia gas (NH₃) required to fill a volume of 50 liters, you can use the formula: moles = volume (liters) / volume per mole (liters/mole). Therefore, the calculation is 50 liters / 22.4 liters/mole = approximately 2.24 moles of NH₃ are needed.
To convert from standard liters per minute (slpm) to liters per minute (lpm), you need to know the standard conditions under which the slpm measurement was taken, as slpm refers to a volume flow rate at specific temperature and pressure conditions. If you are at the same conditions, 1 slpm equals 1 lpm. However, if conditions differ, you would use the ideal gas law or appropriate conversion factors to adjust for temperature and pressure differences, which may require specific calculations based on the gas properties.
39.25 liters.
The molar volume of nitrogen gas at standard temperature and pressure (STP) is approximately 22.4 liters. This means that 1 mole of nitrogen gas occupies 22.4 liters of space under these conditions.