2c2h6+702=4co2+6h20
2moles of ethane :7 moles of oxygen
0.9333 of ethane:?
cross multiply it and the answer will be 3.266666
The molar volume of an ideal gas is 22,414 at 0 0C and 1 atmosphere; this value is variable with the temperature and pressure.
3.5
0.25 moles, approx.
The gas would occupy 40 liters of space, by volume. This is only true as long as the conditions were normal.
That is the element potassium at STANDARD TEMPERATURE AND PRESSURE. Standard temperature is 273 K and standard pressure is 1 atm.
The density of the 0.946 liters should be given. However, assuming fresh water at room temperature with density 1 gram/cubic cm or 1 gram/ml, then: 0.946 liters = 946 milliliters = 946 grams
Assuming no change in temperature and pressure, calculate the volume of O2 (in liters) required for the complete combustion of 14.9 L of butane (C4H10):
88
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
Ethane is C2H6.The answer is 24,23 L water vapors (for a density of 0,804 g/cm3).
Standard Liter per minute (SLPM) refers to the flow rate of a gas at "standard conditions" (usually sea level pressure, room temperature..etc) Liter per minute (LPM) is the flow rate at the conditions being measured. This is an important distinction when measuring compressed gasses. One liter of compressed gas will expand to a higher volume at standard conditions.
The number of moles of helium is 0,32.
0.25 moles, approx.
The gas would occupy 40 liters of space, by volume. This is only true as long as the conditions were normal.
at STP 1 mole occupies 22.4 litres. 64.28 / 22.4 is 2.8696428 moles. Multiply this by avagadro's constant (6.022*10^23) gives 1.7281x10^24 molecules
39.25 liters.
That depends on the model of the transformer. I have seen transformers that required 7500 liters and some that needed 2,5 liters.
No, all pure water boils at 100oC., 212oF., assuming all other 'standard' conditions apply.
No, all pure water boils at 100oC., 212oF., assuming all other 'standard' conditions apply.