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0.0513 mol

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12y ago

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How many moles of Pt are in a 455-mg ring of pure platinum?

To find the number of moles of Pt in the ring, you first need to convert the mass of the ring from milligrams to grams (since 1 gram = 1000 milligrams). Then, divide the mass in grams by the molar mass of platinum (approximately 195.08 g/mol) to find the number of moles of Pt in the ring.


What are some other markings for platinum?

PT. 950, PT. 900, Plat. Platinum, 10% Irid. 90% Plat. All of these can be markings for platinum.


How many protons are found in an atom of platinum (Pt)?

An atom of platinum (Pt) has 78 protons.


What is the chemical symbol for platinum?

The chemical symbol for gold is Au, silver is Ag, and platinum is Pt.


What is the element name for Pt?

Pt is the symbol for platinum, which is a silvery white metal that is malleable and ductile. Its atomic number is 78, and its atomic weight is 195.084. Platinum is in group 10, period 6.


Is Pt for platinum?

Yes, Pt is platinum's chemical symbol.


What is the symbol of Platinum?

Platinum is a chemical element with the chemical symbol Pt and an atomic number of 78.The periodic symbol of Platinum is Pt.


What is the chemical abbreviation of platinum?

The elemental symbol for Platinum is Pt.


Of the elements Pt Ca Li and Kr which is a transition metal?

It is Pt = platinum.


How many atoms does Pt have?

The element platinum has only one atom.


Is 1.11 mole Pt more or less than 6.022 x 1023 atoms?

It is more because 1 mol of platinum is 6.022 X 10^23 atoms, therefore 1.11 moles of platinum would be more.


What volume of M AgNI would be required to precipitate all in ml of solution that containing Pt?

To determine the volume of M AgNI required to precipitate all of the platinum (Pt) in a solution, you need to know the concentration of Pt in the solution and the stoichiometry of the reaction between AgNI and Pt. Assuming you have the molarity of Pt and its molar mass, you can calculate the moles of Pt present. Then, using the 1:1 molar ratio of AgNI to Pt, you can find the required volume of AgNI by dividing the moles of AgNI needed by its molarity. Without specific values, I cannot provide an exact volume.