0.0513 mol
To find the number of moles of Pt in the ring, you first need to convert the mass of the ring from milligrams to grams (since 1 gram = 1000 milligrams). Then, divide the mass in grams by the molar mass of platinum (approximately 195.08 g/mol) to find the number of moles of Pt in the ring.
The chemical symbol for gold is Au, silver is Ag, and platinum is Pt.
The elemental symbol for Platinum is Pt.
It is more because 1 mol of platinum is 6.022 X 10^23 atoms, therefore 1.11 moles of platinum would be more.
The chemical symbol of platinum is Pt. This element has an atomic weight of 78 and was discovered in 1735.
To find the number of moles of Pt in the ring, you first need to convert the mass of the ring from milligrams to grams (since 1 gram = 1000 milligrams). Then, divide the mass in grams by the molar mass of platinum (approximately 195.08 g/mol) to find the number of moles of Pt in the ring.
PT. 950, PT. 900, Plat. Platinum, 10% Irid. 90% Plat. All of these can be markings for platinum.
An atom of platinum (Pt) has 78 protons.
The chemical symbol for gold is Au, silver is Ag, and platinum is Pt.
Pt is the symbol for platinum, which is a silvery white metal that is malleable and ductile. Its atomic number is 78, and its atomic weight is 195.084. Platinum is in group 10, period 6.
Yes, Pt is platinum's chemical symbol.
Platinum is a chemical element with the chemical symbol Pt and an atomic number of 78.The periodic symbol of Platinum is Pt.
The elemental symbol for Platinum is Pt.
It is Pt = platinum.
The element platinum has only one atom.
It is more because 1 mol of platinum is 6.022 X 10^23 atoms, therefore 1.11 moles of platinum would be more.
To determine the volume of M AgNI required to precipitate all of the platinum (Pt) in a solution, you need to know the concentration of Pt in the solution and the stoichiometry of the reaction between AgNI and Pt. Assuming you have the molarity of Pt and its molar mass, you can calculate the moles of Pt present. Then, using the 1:1 molar ratio of AgNI to Pt, you can find the required volume of AgNI by dividing the moles of AgNI needed by its molarity. Without specific values, I cannot provide an exact volume.