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How many moles of sodium chloride are in 5.08 L of a 2.36 M solution?
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
How many moles of sodium chhloride are present in 22.0 ml of 0.500 m solution?
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
How many moles of Lithium chloride need to be added to one liter of total solution to make up a 1.25 M solution?
To make a 1.25 M solution of lithium chloride in one liter of total solution, you need 1.25 moles of lithium chloride. This is because the concentration of a solution in moles per liter is equal to the number of moles of solute divided by the volume of the solution in liters.
How many moles of sodium are in 4.0 moles of NaCl?
Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
How many moles of sodium chloride are present if you have a sodium chloride solution of 2.15 m with a volume of 50.0 ml?
Sodium and chloride have fixed oxidation states. Sodium is Na+ and Chloride is Cl-. Their ratio is 1:1 (1 to 1). So in this particular compound, there is only one sodium ion and 1 x 2.5 = 2.5 moles (answer).
How many moles of sodium chloride solute are in 155 grams of an 85.5 percent by mass solution?
To find the moles of sodium chloride solute in 155 grams of an 85.5% solution, first calculate the mass of sodium chloride present in the solution (mass percent x mass of solution). Then, convert the mass of sodium chloride to moles using its molar mass (58.44 g/mol). This will give you the number of moles of sodium chloride solute in the solution.
How many moles of sodium chloride are in 400 mL of a 6 M NaCl solution?
The answer is 2,4 moles.
How many moles of sodium chloride are in 5.08 L of a 2.36 M solution?
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
How many moles of sodium chloride are there in 250 mL of a 1.20 M sodium chloride solution?
To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.
How many mols of NaCl are present in 1 liter of a 0.1M solution of sodium chloride?
There would be 0.1 moles of NaCl present in 1 liter of a 0.1M solution of sodium chloride. This is based on the definition of molarity which is moles of solute per liter of solution.
How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?
In a 1M solution of sodium chloride, there would be 1 mole of sodium ions and 1 mole of chloride ions in 1 liter of the solution. This is because each formula unit of sodium chloride dissociates into one sodium ion and one chloride ion in solution.
How many moles of sodium are needed to make 3.6 moles of sodium chloride?
One mole of sodium chloride is composed of one mole of sodium atoms. Therefore, 3.6 moles of sodium chloride would require 3.6 moles of sodium.
How many grams are in 0.40 moles of sodium chloride?
0,40 moles of sodium chloride contain 23,376 g.
How many moles are in 10.24g sodium chloride?
The answer is 0,175 moles.
How many grams are in four tenths moles of sodium chloride?
23.3772 grams are there in four tenths moles of sodium chloride
How many moles each of Na and Cl are in 0.500L of the saline solution?
This depends on the concentration of sodium chloride in water.
How many moles of sodium chhloride are present in 22.0 ml of 0.500 m solution?
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
