You have answered the question for yourself.
4 Na + O2 = 2Na2O
The molar ratios are 4:1 :: 2
The answer is '2'.
Four moles of sodium plus 1 mole of oxygen gas produces 2 moles sodium oxide. 4Na + O2 --->2Na2O
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
From the balanced equation, 2 moles of A3 react with 3 moles of B2 to produce 6 moles of AB. Therefore, if 10 moles of A3 are reacted, the ratio of moles of AB produced would be (10 moles A3 / 2 moles A3) * 6 moles AB = 30 moles AB.
There are a total of 8 atoms in the chemical equation 4Na + O2 → 2Na2O. This can be calculated by adding up the number of atoms on both sides of the equation: 4 sodium atoms from 4Na, 2 oxygen atoms from O2, and 2 oxygen atoms from 2Na2O. Thus, the total number of atoms is 4 + 2 + 2 = 8 atoms.
Four moles of sodium plus 1 mole of oxygen gas produces 2 moles sodium oxide. 4Na + O2 --->2Na2O
5 moles RbNO3 (3 moles O2/2 moles RbNO3) = 7.5 moles oxygen gas produced
N2H4 + 2H2O2 -> N2 + 4H2O 1.5 moles N2H4 (4 mole H2O/1 mole N2H4) = 6.0 moles water produced
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
The answer is one mole.
From the balanced equation, 2 moles of A3 react with 3 moles of B2 to produce 6 moles of AB. Therefore, if 10 moles of A3 are reacted, the ratio of moles of AB produced would be (10 moles A3 / 2 moles A3) * 6 moles AB = 30 moles AB.
1
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
There are a total of 8 atoms in the chemical equation 4Na + O2 → 2Na2O. This can be calculated by adding up the number of atoms on both sides of the equation: 4 sodium atoms from 4Na, 2 oxygen atoms from O2, and 2 oxygen atoms from 2Na2O. Thus, the total number of atoms is 4 + 2 + 2 = 8 atoms.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
CaC2 + 2H2O ==> C2H2 + Ca(OH)2moles of C2H2 produced = moles of Ca(OH)2 produced (1:1 mole ratio is the stoichiometry)moles of Ca(OH)2 produced = 7 g x 1mol/74.1 g = 0.0945 molesmoles C2H2 = 0.0945 molesgrams C2H2 = 0.0945 moles x 26 g/mole = 2.46 grams = 2 grams to 1 sig fig
For every 2 moles of A3, 3 moles of B2 react to form 6 moles of AB. Since we have 10 moles of A3, we need to double the moles of B2 reacting, which would be 15 moles of B2 to fully react with the 10 moles of A3. This would produce 30 moles of AB.