1, the basis of life is the element carbon.
57, the number of protons determines the elements number.
There are 3 elements and they are carbon (C), hydrogen (H) and Oxygen (O). The number of atoms depends on the number of molecules you have. In on molecule of C2H5OH there are 9 atoms.
i believe it is 57 do.If im wrong then im wrong im very sorry if i am.
Today all elements up to atomic number 98 (including Cf) are considered as natural chemical elements.
4.See the Related Questions for how to determine the number of electrons in the outermost shell of all the elements!
The number of subjects will depend on what the elements of the set are. The number of subsets is 2a.
Each bio-molecule has a specific chemical formula and a different number of atoms; generally bio-molecules contain C, H, O, N.
A: 9 students take biology but not history. B: 11 take neither bio nor history. Reasons: A: 9 is the answer because if you subtract the number of students who take history and bio (8) from the total number of bio students (17) you get 9 (the remaining number of bio students who do not take history). B: 11 is the answer because a total of 22 students take history. however, 8 students take bio and history, and before, we found that 9 students only take bio. Therefore, if we add up the number of only bio students and history students (of which some also take bio, but are not exclusively bio), we get 31 students. If we subtract 31 from 42 (the total number of students), we get 11 remaining students who are in neither bio nor history.
there is no such limitation. you can have any number of form elements
KNO3 has 3 elements which are potassium, Nitrogen and Oxygen.
1
512 subsets
03343329318 with bio data chaek
That would be the Atomic number. It tells you how many protons are contained in the nucleus of an atom. No two elements could share this number.
57, the number of protons determines the elements number.
The number of elements that contain the same type of outer electrons as sodium is 11.
Heavy metals like mercury (Hg) and Lead (Pb)