These elements are B, Al Br.
Iodine has one unpaired electron in its ground state.
There are three unpaired electrons in an atom of cobalt in its ground state. This can be determined by the electron configuration of cobalt, which is [Ar] 4s2 3d7. The 3d orbital has 5 electrons, so there are 3 unpaired electrons.
In its ground state, rhenium (Re) has 1 unpaired electron.
There are three unpaired electrons in the ground state of a scandium atom (Sc). This is because scandium has an atomic number of 21, with an electron configuration of [Ar] 3d^1 4s^2, where the 3d orbital has one unpaired electron.
thee are exactly 10 that is a difficult question but yes it is 10
In the ground state, only one of the elements listed has 1 unpaired electron: aluminum (Al). Boron (B) has 3 unpaired electrons, oxygen (O) has 2 unpaired electrons, and fluorine (F) has 1 unpaired electron but is already fully paired in its 2p orbital. Therefore, the total count of elements with 1 unpaired electron is two: Al and F.
Iodine has one unpaired electron in its ground state.
There are three unpaired electrons in an atom of cobalt in its ground state. This can be determined by the electron configuration of cobalt, which is [Ar] 4s2 3d7. The 3d orbital has 5 electrons, so there are 3 unpaired electrons.
In its ground state, rhenium (Re) has 1 unpaired electron.
Noble gases, like helium, neon, and argon, have no unpaired electrons in their ground state electron configuration. This means that all of their electrons are paired up in orbitals.
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There are three unpaired electrons in the ground state of a scandium atom (Sc). This is because scandium has an atomic number of 21, with an electron configuration of [Ar] 3d^1 4s^2, where the 3d orbital has one unpaired electron.
thee are exactly 10 that is a difficult question but yes it is 10
The first-row transition metal with the most unpaired electrons is manganese (Mn). Its expected ground-state electron configuration is [Ar] 3d5 4s2, meaning it has 5 unpaired electrons in the 3d subshell.
Magnesium has five unpaired electrons and is therefor paramagnetic
There are 0 unpaired electrons which would make it diamagnetic
The element with three unpaired electrons in its p orbital is phosphorus. Its electron configuration is [Ne] 3s^2 3p^3, where the last three electrons occupy three separate p orbitals, each with one unpaired electron.