Here are 5 significant figures.
c(NO3)= 336 g/L or c(NO3) = 5.42 mol/L (3 sig fig)
Only 3 significant figures, after rounding.
0.33 mol/kg (apex)
Because some part of your equation has a figure that limits how many sig figs you can use. Remember the number of sig figs is symbolic of how precise the initial measurements were. For example the number 2.4 is not as precise as 2.45298. So your answer can only be as precise as the LEAST precise measurement you have taken or been given. So in my example above if 2.4 is the least precise measurement then you can only have an answer with two sig figs.
in addition/subtraction you use the most number of sig figs. So in this case you need 5 sig figs in the answer.
It depends to how many significant figures: 1 sig fig => 10 (technically 1 x 101 or 1e1) 2 sig fig => 13 3 sig fig => 12.7 4 sig fig => 12.74 5 sig fig => 12.744
There is one sig fig
Two of them
3 sig figs
There is one sig fig in the number 4000.
There is one sig fig in the number 1.
There is 1 sig fig in the number 2.
Three sig(nificant) fig(ure)s in '402'.
There are 4 sig. fig.
2x1.0079 =2.0158 has 1 sig fig because u have to use the smallest sig fig that was in the whole calculation which was 2, therefore the 2 in 2.0158 is the only sig fig
There is 1 sig fig.
there are 4 sig. fig. in 1001