How many sulfur atoms are present in 25.6 g of Al2(S2O3)3?

Answer 1

First of all, your formula cannot be right. There is no way the formula is Al2S2O33. Sorry, not happening. Maybe it is supposed to be Al2S2O3? But you need to know the actual formula to answer this question.

Step 1) Once you have the correct formula, determine the molecular weight of this compound. See the Related Questions link to the left for how to do that.

Step 2) Then convert the 25.6 grams of whatever this stuff is into moles. See the Related Questions links to the left for how to convert grams into moles.

Step 3) Then based on the formula (as it is now), there are 2 atoms of sulfur for every molecule of this stuff. That means however many molecules you calculated in Step 2 above, you have twice as many moles of sulfur.

Step 4) Then convert from moles to atoms. To do that multiply by Avogadro's number and see the Related Questions links for how to do that!

Answer 2

There are 6 sulfur atoms in Al2(S2O3)3. To calculate the number of sulfur atoms in 25.6 g of Al2(S2O3)3, you need to determine the molar mass of Al2(S2O3)3 (which includes the mass of sulfur) and then use stoichiometry to find the number of moles of Al2(S2O3)3 in 25.6 g. Finally, you can use the mole ratio to find the number of sulfur atoms.