Alkanes are CnH2n+2, so for 5 carbon alkane, n = 10+2 =12 or 12 hydrogen atoms. It would be like this..
CH3CH2CH2CH2CH3
An alkane with six carbon atoms would be hexane (C6H14). Since each carbon atom is bonded to two hydrogen atoms in an alkane, you would have 6 carbon atoms x 2 hydrogen atoms per carbon = 12 hydrogen atoms.
In an alkane the number of hydrogen atoms is two greater than twice the number of carbon atoms. If we reverse this rule, we find that the number of carbon atoms is one less than half the number of hydrogen atoms. 32/2=16 16-1=15 So our alkane would have 15 carbon atoms. This alkane would be pentadecane or one of its isomers.
The generic formula for an alkane is CnH(2n + 2).Therefore, an alkane with 3 carbon atoms would have 8 hydrogen atoms.
In an alkane molecule with ten carbon atoms, the general formula is C10H22. Each carbon atom forms four bonds, leaving 22 hydrogen atoms to satisfy the valency requirement of carbon. So, there are 22 hydrogen atoms in an alkane molecule with ten carbon atoms.
In an alkane, each carbon atom is bonded to 4 hydrogen atoms. So, the number of hydrogens in an alkane can be determined by the formula 2n+2, where n is the number of carbon atoms in the alkane.
A non cyclic alkane always has a number of hydrogen atoms equal to 2c + 2, where c is the number of carbon atoms. Therefore, hexadecane, an alkane with 16 carbon atoms, will have 34 hydrogen atoms.
An alkane with six carbon atoms would be hexane (C6H14). Since each carbon atom is bonded to two hydrogen atoms in an alkane, you would have 6 carbon atoms x 2 hydrogen atoms per carbon = 12 hydrogen atoms.
In an alkane the number of hydrogen atoms is two greater than twice the number of carbon atoms. If we reverse this rule, we find that the number of carbon atoms is one less than half the number of hydrogen atoms. 32/2=16 16-1=15 So our alkane would have 15 carbon atoms. This alkane would be pentadecane or one of its isomers.
The generic formula for an alkane is CnH(2n + 2).Therefore, an alkane with 3 carbon atoms would have 8 hydrogen atoms.
In an alkane molecule with ten carbon atoms, the general formula is C10H22. Each carbon atom forms four bonds, leaving 22 hydrogen atoms to satisfy the valency requirement of carbon. So, there are 22 hydrogen atoms in an alkane molecule with ten carbon atoms.
In an alkane, each carbon atom is bonded to 4 hydrogen atoms. So, the number of hydrogens in an alkane can be determined by the formula 2n+2, where n is the number of carbon atoms in the alkane.
Then the acyclic alkane hydrocarbon contains 2n+2 hydrogen atoms.
An acyclic alkane with 13 carbon atoms will have 28 hydrogen atoms. This is because each carbon atom in an alkane forms 4 single bonds with other atoms, and in this case, each of the 13 carbon atoms will form single bonds with 2 hydrogen atoms and 2 other carbon atoms.
A 4 carbon linear alkane, such as butane, has the chemical formula C4H10 because each carbon atom in the chain can form bonds with 3 hydrogen atoms. In contrast, a 4 carbon cyclic alkane, such as cyclobutane, has the chemical formula C4H8 because two of the carbon atoms in the ring are involved in forming the ring structure and cannot form bonds with additional hydrogen atoms.
The compound C8H18 is composed of carbon and hydrogen atoms. It is an alkane known as octane, with 8 carbon atoms and 18 hydrogen atoms in its chemical structure.
Formula for alkanes:Number of H = 2 * number of C + 2So, using this formula, H = 2 * 10 + 2, which gives 22
halo alkane or alkyl halides