One calcium atom will transfer one of each of its two valence electrons to one each of two iodine atoms. In the process, the calcium atom becomes a calcium ion with a 2+ charge, and each iodine atom becomes an iodide ion with a 1- charge. The opposite charges between the iodide and calcium ions form an electrostatic attraction called an ionic bond, forming the ionic compound calcium iodide.
Ca + I2 ---> I- + Ca2+ + I- ---> CaI2
Two valence electrons are transferred from the calcium atom to the iodine atom in the formation of calcium iodide. This transfer results in the formation of calcium ions (Ca2+) and iodide ions (I-), which then form an ionic bond to create the compound calcium iodide (CaI2).
during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
In the compound calcium iodide, one calcium atom transfers 2 electrons to one iodine atom. This results in both atoms achieving a stable electron configuration – calcium with a full outer shell and iodine with a complete octet.
Two valence electrons are donated to two I atoms (or one I2 molecule) Ca --> Ca2+ + 2 e- 2 e- + I2 --> 2 I- In this way, taking both together CaI2, calcium iodide, is formed.
Calcium nitride has an ionic bond. Calcium, a metal, donates two electrons to nitrogen, a nonmetal, resulting in the formation of an ionic compound with a +2 charge on calcium and a -3 charge on nitrogen.
Two valence electrons are transferred from the calcium atom to the iodine atom in the formation of calcium iodide. This transfer results in the formation of calcium ions (Ca2+) and iodide ions (I-), which then form an ionic bond to create the compound calcium iodide (CaI2).
The formula for calcium iodide is CaI2. This means that the calcium atom has transferred one electron to each of two iodine atoms, for a total of two electrons transferred.
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during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
In the compound calcium iodide, one calcium atom transfers 2 electrons to one iodine atom. This results in both atoms achieving a stable electron configuration – calcium with a full outer shell and iodine with a complete octet.
I believe you mean the formation of the compound calcium iodide. In the formation of calcium iodide, CaI2, the calcium atom transfers two valence electrons to two iodine atoms, with one electron going to each iodine atom. This causes the formation of a calcium ion, Ca2+, and two iodide ions, I-. The electrostatic attraction between the oppositely charged ions forms the ionic bonds that form the compound calcium iodide.
Two valence electrons are donated to two I atoms (or one I2 molecule) Ca --> Ca2+ + 2 e- 2 e- + I2 --> 2 I- In this way, taking both together CaI2, calcium iodide, is formed.
Calcium nitride has an ionic bond. Calcium, a metal, donates two electrons to nitrogen, a nonmetal, resulting in the formation of an ionic compound with a +2 charge on calcium and a -3 charge on nitrogen.
Calcium fluoride is an example of an ionic compound, not a covalent compound. Covalent compounds form between two nonmetals, while ionic compounds form between a metal and a nonmetal.
To make calcium iodide, calcium transfers two valence electrons to iodine. Calcium wants to lose two electrons to achieve a stable octet configuration, while iodine needs two electrons to complete its octet. This transfer results in the formation of CaI2 with a 2:1 ratio of calcium to iodine atoms.
When calcium reacts with oxygen atoms, the outer shell electrons of calcium are transferred to oxygen atoms. This leads to the formation of calcium oxide (CaO) with calcium losing 2 electrons to form a Ca2+ ion and oxygen gaining 2 electrons to form an O2- ion.
It would be a compound, made of Calcium and Oxygen.