The Lewis dot structure representing chloroform (CCl3H) has valence electrons surrounding all chlorines and the central carbon. The lone hydrogen will have dots only on one side with the other three open. The Lewis dot structure is: H.. .. ..:C:C:Cl: .. .. .. :C: ..
Chloroform , formula is 'CCl3H'. It is dissolved in a spirit, such as an alcohol. It modern IUPAC name is 'Tri-chloromethane'.
I assume that these are weight percents. If so, assume you have 100 g of the substance. Then divide each by the molecular weight to find the number of moles of C, H, & Cl.C: 18.28 g * (1 mole C/12.011 g C) = 1.522 moles CH: 0.77 g * (1 mole H/1.008 g H) = 0.764 moles HCl: 80.95 g * (1 mole Cl/35.453 g Cl) = 2.283 moles ClNext find the ratio of moles of C to H to Cl. To do this divide each by the smallest number of moles from the list, in this case it will be hydrogen.C: 1.522/0.764 = 1.99 (round it to 2)H: 0.764/0.764 = 1.00Cl: 2.283/0.764 = 2.99 (round it to 3)So your empirical formula of the pesticide should be C2HCl3
The H-C bond and each C-Cl bond are covalent bonds.
Chloroform , formula is 'CCl3H'. It is dissolved in a spirit, such as an alcohol. It modern IUPAC name is 'Tri-chloromethane'.
I assume that these are weight percents. If so, assume you have 100 g of the substance. Then divide each by the molecular weight to find the number of moles of C, H, & Cl.C: 18.28 g * (1 mole C/12.011 g C) = 1.522 moles CH: 0.77 g * (1 mole H/1.008 g H) = 0.764 moles HCl: 80.95 g * (1 mole Cl/35.453 g Cl) = 2.283 moles ClNext find the ratio of moles of C to H to Cl. To do this divide each by the smallest number of moles from the list, in this case it will be hydrogen.C: 1.522/0.764 = 1.99 (round it to 2)H: 0.764/0.764 = 1.00Cl: 2.283/0.764 = 2.99 (round it to 3)So your empirical formula of the pesticide should be C2HCl3