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What does 65g mg?

It appears that "65g mg" is unclear and does not make sense. If you provide more context or clarify the question, I would be happy to help answer it.


How many kilograms in 65g?

One kg = 1000 grams. So one gram is 10^-3 kilograms. One milli gram is 10^-3 gram = 10^-6 kg. Kilograms and grams are both the metric units of mass. So the answer is 0.065 KG


What is the percent yield for iron if the reaction of 65.0 g of iron oxide produces 33.0 g of iron?

Well, I ran the numbers for what you have in the question, and it didn't make sense, so I'm assuming you really mean 65g of iron yields 33g iron oxide. I'm also assuming you mean iron(III) oxide, which is iron's most common valence state when it reacts with oxygen, which means the product's formula would be Fe2O3.With those things in mind, here's your balanced equation:4Fe + 3O2 --> 2Fe2O3.Step1: given 65g Fe, how many moles is that? Direct proportion between 65g and the unknown # of moles and iron's atomic mass of 56g/mol gives us 1.16 moles of iron.Step 2: molar ratio of iron to iron(III) oxide is 4-2, which simplifies to 2-1, so you will have 0.58 moles of product.Step 3: given 0.58 moles of product, set up another direct proportion with the unknown mass over given moles equal to iron(III) oxide's molar mass of 160g/mol to get a mass of 92.8g theoretical yield of product.Step 4: your actual yield was 33g, so divide that by the stoichiometric yield of 92.8g, which is 0.355, which means about a 36% actual yield, which is the answer.


Which object will displaced more water if object A equals 500grams and a density of 5 gram per cubic centimeter object B equals 650 grams and density of 65gram per cubic centimeter?

Object A, 500g/5g/cm3 = 100 cm3 Object B, 650g/65g/cm3 = 10 cm3 Object A displaces more water.


What is the percent yield of h2o if 58g h2o are produced by combining 60g o2 and 7g h2?

Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%